[SOLVED] If condition fails--even though it SHOULD run

[doni49]

I've been trying to figure this out since last night.

 

PLEASE help me find it.

 

$la[0] contains X-Folder: but the if test seems to think that it doesn't.

THis is a code snippet from my code.

---

echo "Line" . $cnt++ . ":  Part 0--" . $la[0] . "--Part 1--" . $la[1] . "--<br>\n";

---

produces this:

Line16: Part 0--X-Folder:--Part 1--0--

 

But the following if test condition fails:

---

                  if ($la[0] == "X-Folder:"){
                     $folder = $la[1];
                     echo "Line:  " . $line;
                     $tst = FALSE;
                   }

[Barand]

Is there any code between

 

<?php
echo "Line" . $cnt++ . ":  Part 0--" . $la[0] . "--Part 1--" . $la[1] . "--<br>\n";
?>

 

and

 

<?php
if ($la[0] == "X-Folder:"){
     $folder = $la[1];
     echo "Line:  " . $line;
     $tst = FALSE;
}
?>

[mainewoods]

display it's value just before your test:

echo "showvalue: " . $la[0];
if ($la[0] == "X-Folder:"){
    $folder = $la[1];
    echo "Line:  " . $line;
    $tst = FALSE;
}

[doni49]

Is there any code between

 

<?php
echo "Line" . $cnt++ . ":  Part 0--" . $la[0] . "--Part 1--" . $la[1] . "--<br>\n";
?>

 

and

 

<?php
if ($la[0] == "X-Folder:"){
     $folder = $la[1];
     echo "Line:  " . $line;
     $tst = FALSE;
}
?>

Nope.  Just a comment.  I put the echo line in there because I wanted to confirm that the $la array had what I thought it did.

 

Here's the more of the code just copy pasted.

 

                   echo "Line" . $cnt++ . ":  Part 0--" . $la[0] . "--Part 1--" . $la[1] . "--<br>\n";
//                   echo "Line" . $cnt++ . ":  " . $line[$cnt] . "<br>\n";

                   if ($la[0] == "X-Folder:"){
                     $folder = $la[1];
                     echo "Line:  " . $line;
                     $tst = FALSE;
                   }

 

I put the dashes before and after the variable because I wanted to see if there were any extra characters in there.

 

Thanks guys!

 

display it's value just before your test:

That's what the echo line that I have is for.

 

Thanks all for the assistance--this one's been bugging me and I'm sure it's probably a simple typo somewhere.  But I've been looking at it for so long, I'm not sure I'll be able to see it myself.

[AndyB]

I suspect that $la[0] might contain some leading or trailing blanks, or it's managed to get some non-printing control character (or MS Word garbage) in there perhaps.  Test it thoroughly by echoing the value AND the length of the string.

[doni49]

Thanks for the suggestion Andy.  You were right.  Now I just need to figure out WHY.  I (or actually my PHP script) wrote the text file that this is coming from.  I'm reading a text file in and trying to pull out the value that follows the colon on the following line.

X-Folder: 0

 

Here's the code that wrote this line to the file.

---

   $hdrs[$i-1] = "X-Folder:  " . $folder ."\n\n";
   $headers = implode("\n", $hdrs);
   $fname = time();
   $filePath = $path . $folders[$folder] . "/";
   $filenameTMP = $filePath . "tmp/" . $fname;
   if (!$handle = fopen($filenameTMP, 'w')) {
         echo "Cannot open file ($filenameTMP)";
         exit;
   }

   // Write $somecontent to our opened file.

   $content = $headers . $message;
   if (fwrite($handle, $content) === FALSE) {
       echo "Cannot write to file ($filenameTMP)";
       exit;
   }

   fclose($handle);

 

 

[doni49]

P.S.  I used strlen on both.

 

strlen($la[0]); //  <--returns 13

 

and

 

strlen("X-Folder:");//  <--returns 9

[AndyB]

... wonder if those 'extra' four characters are \r\n in your text file

[doni49]

Interesting theory.  But:

 

1) I thought \n was seen as ONE LINE.  A new-line character.

 

2) the $la array variable was created from this code:

$la = explode(" ",$lines[$cnt]);

 

So if anything the newline would be at the end of $la.

 

I was getting ready to post that--but decided to try something first. 

$l = strlen("\n\nX-Folder:");  //  <--returns 11 instead of 9

 

and changed the if condition to this.

if ($la[0] == "\n\nX-Folder:")  //<--still doesn't run.

 

[doni49]

found it there was a typo in the echo statement that's inside of the if statement.  Since it wasn't displaying what I expected, I didn't think it was working.

 

Thanks for the assistance!