convertion dates

[Jay2391]

I want to convert that date('U'); number into a date can i do that ???

 

???

 

 

$ut = date('U');

$rt = 1173128934 + 86400;

$tbthere = $rt - $ut;

echo "<br><br>$ut";

echo "<br><be>$rt";

echo "<br><be>$tbthere";

[JBS103]

You want to convert date('U') into readable text? I don't understand.

 

You can just change the "U" to something like "d-m-Y" and it will output it in a different format.

[Jay2391]

sorry if i didn't explain I want to change the date('U');

to day, month, year , time  format

[pocobueno1388]

date('d-m-Y');

[Jay2391]

well i know how to do that .... but i need to do it in seconds first....why bacause what i am trying to do is set up a time with in 24hrs of the original time and have a auto counter that will keep track....

 

so with dates i can't figure out but with seconds i can do it really easy...

 

so the question is can i convert that number into a actual date format????

[kenrbnsn]

The second parameter of the date() function is the seconds since 1-1-1970, so

<?php
$u = date('U');
echo date('Y-m-d',$u);
?>

 

Ken

[Jay2391]

cool thanks

[Jay2391]

why is my date not giving the correct info...

 

 

///////////I set up a static time and add one full day

$rt = 1173128934 + 86400;

 

///////////////i get todays date

$ut = date('U');

 

////////////////i substract todays date to the static time and try to get the difference

$tbthere = $rt - $ut;

 

 

//////////////I convert and echo

 

 

//////////i get the correct time

echo date('Y-m-d / H:m',$ut);

echo "<br>";

////////////i get the correct time

echo date('Y-m-d / H:m',$rt);

echo "<br>";

 

Incorrect time ???? why is that ????

echo date('H:m',$tbthere);

[kenrbnsn]

The reason it is not displaying what you want is that the second argument for the date() function is an integer representing the number of seconds since 1-1-1970. What you are passing it is a number representing the number of second between two times. BTW, the format string you're using, "H:m", does not print hours & minutes. The "m" is for the number of the current month, you want to use the "i" to get minutes -- "H:i".

 

One solution to your problem would be to get the the number of seconds since 1-1-1970 of any date at midnight, add your value to it and format that number as "H:i":

<?php
///////////I set up a static time and add one full day
$rt = 1173128934 + 86400;

///////////////i get todays date
$ut = date('U');

////////////////i substract todays date to the static time and try to get the difference
$tbthere = $rt - $ut;


//////////////I convert and echo


//////////i get the correct time
echo date('Y-m-d / H:i',$ut) . '<br>';

////////////i get the correct time
echo date('Y-m-d / H:i',$rt) . '<br>';

// Echo the correct formatted difference
echo date('H:i',strtotime('3/3/2007 00:00') + $tbthere) . '<br>';
?>

 

Ken

[Jay2391]

May be i miss read something I see that it dosen't really work

 

2007-03-06 / 12:14  correct  current time

2007-03-07 / 16:08  day and time expiration

03:54    ---this should be  27:54 because this is how many hours to reach the exp date and time

 

I know you mention about getting a time at midnight ....

 

strtotime('3/3/2007 00:00')

 

but you did that already .... so what do you mean another substraction then ???

[kenrbnsn]

My method only works if the difference is less than a day.

 

As a general method, try this:

<?php
$diff_hours = floor($tbthere / 3600);
$diff_mins = floor($tbthere % 3600)/60;
echo sprintf("<br>%02d:%02d",$diff_hours,$diff_mins);
?>

 

Ken

[Jay2391]

my plan is to alway be less than a day but the extra info and code didn't hurt .... thanks that work not quite sure how you  did it

but it works, I willl take a closer look at the code and try to understand i hate when I am all confuse, LOL  ..Thanks Again!!!!