How to get a URL that sent a visitor to the site

[Wildhalf]

Hi,

 

I need some help...

 

I have the code below working for XAMP when i use the URL

        http://127.0.0.1/paypal/test/test2.html

test2.html contains a link to a php file on my site with the

code below. This Works when i use it this way..

 

But when i am testing it through PAYPAL Sandbox the code

doesn't work. It returns a NULL for the URL.

 

Is this because Sandbox uses HTTPS??

 

If so how do i get this working for HTTPS?

 

<?
/*Gets URL that sent visitor to the site */
$referrer_url = $_SERVER['HTTP_REFERER'];

print "Referral URL : $referrer_url</br>";

/*Checks to see if paypal is in the URL*/
ereg ("paypal", $referrer_url, $domain);

print "Referral URL : $domain[0]</br>";

If ($domain[0] == 'paypal'){
echo '</br>This works </br>';
include "main.html";
exit();
}
?>

 

Thanks in advance,

 

Kieron

[skali]

$_SERVER['HTTP_REFERER']

[Wildhalf]

Thanks but if you look at my code i am using this. Which works fine for one intance but when passing through PAYPAL Sandboax it doesn't work...

 

Is there a way to pull the URL from the last page visited from the history

[Wildhalf]

Does anyone have any ideas???