Whats wrong with this?

[R1der]

if($gangdata['gangPIC']) //line 62
{
print "<img src='{$gangdata['gangPIC']}' alt='Gang Picture' width='468' height='60' /><hr />";
}
else
{
print "<b>No Gang Picture</b><hr />";
}

 

I get this error

 

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /****/******/*******/******.php on line 62

 

It all worked fine till i added that, i could'nt spot a problem with it and its prob something simple.

 

Thanks for your time

[Orio]

Can you show the 5 lines before line 62?

 

Orio.

[R1der]

global $ir,$c,$h,$gangdata;
$pq=mysql_query("SELECT * FROM users WHERE userid={$gangdata['gangPRESIDENT']}",$c);
$ldr=mysql_fetch_array($pq);
$vpq=mysql_query("SELECT * FROM users WHERE userid={$gangdata['gangVICEPRES']}",$c);
$coldr=mysql_fetch_array($vpq);
print "<h3><u>{$gangdata['gangNAME']} Gang</u></h3><hr />

[Accurax]

print "<h3><u>{$gangdata['gangNAME']} Gang</u></h3><hr />

 

should be

 

print "<h3><u>{$gangdata['gangNAME']} Gang</u></h3><hr />";

[R1der]

No because it goes like this

 

print "text

text

text

text

text

text

text

text

";

[Accurax]

then can i suggest u post your entire code

[R1der]

I am affraid i cant do that.

 

By doing that people will steal the coding

[R1der]

Dont worry about it, Ill just remove that bit of coding as its fine when i remove that anyways

 

Thanks for your time and your help

[gazalec]

isn't the problem in the if statement

 

You have if(variable) but no operator for example

 

if(variable = 10){
echo "This is ten";
}else{
echo "This is not ten";
}

[JasonLewis]

pfft, lol.

 

if this is 5 lines DIRECTLY above the first code in the first post then you need to close the string ("

 

global $ir,$c,$h,$gangdata;
$pq=mysql_query("SELECT * FROM users WHERE userid={$gangdata['gangPRESIDENT']}",$c);
$ldr=mysql_fetch_array($pq);
$vpq=mysql_query("SELECT * FROM users WHERE userid={$gangdata['gangVICEPRES']}",$c);
$coldr=mysql_fetch_array($vpq);
print "<h3><u>{$gangdata['gangNAME']} Gang</u></h3><hr />";

if($gangdata['gangPIC']) //line 62
{
print "<img src='{$gangdata['gangPIC']}' alt='Gang Picture' width='468' height='60' /><hr />";
}
else
{
print "<b>No Gang Picture</b><hr />";
}

[Accurax]

doesnt if($gangdata['gangPIC'])

 

simply check to see if the array contains anything?

 

hmm.... maybe you do need a != 0 or something to make it work.

 

 

[Accurax]

doesnt if($gangdata['gangPIC'])

 

simply check to see if the array contains anything?

 

hmm.... maybe you do need a != 0 or something to make it work.

 

 

 

allready suggested that .... apparently It is not in fact the 5 lines directly above... and he wont post the rest cos he thinks were theives.

 

just Cant help some people

[JasonLewis]

if the variable you are testing is a boolean then you can just run the if statement like this:

 

$foo = true;

if($foo){
echo "Foo is true";
}else{
echo "Foo is false";
}

or:

$foo = false;

if(!$foo){
echo "Foo is false";
}else{
echo "Foo is true";
}

[redarrow]

I am affraid i cant do that.

By doing that people will steal the coding

 

Your asking for help (free!) but you can not show ur code

but i dont no any php project that has not been done or

supplied free in php, So if your code that inportant dont

ask quistions and read the manual i find your statement a

reel insault but u whant help what a joke?