Jump to content

mysql outpt problem


willwill100

Recommended Posts

Evening guys, I have a problem with my code: no values from the db are outputted. Heres the code:

[code]$result = mysql_query ("SELECT * FROM `competitions`") or die(mysql_error);

while ($row = mysql_fetch_array($result)){

$id=$row['ID'];
$name=$row['name'];
$races=$row['races'];
$qualify=$row['qualify'];
$discards=$row['discards'];
$type=$row['type'];

echo ("<p><b> " . $name . "</b>" . "<br><i>Races: <b>" . $races . "</b> Number to qualify: <b>" . $qualify . "</b> Discards: <b>" . $discards . "</b> Type: <b>" . $type . "</p></i>");
echo (" <a href='$PHP_SELF?deleteme=$id'>Delete Competition</b></a></p> ");

}[/code]

output:

Races: Number to qualify: Discards: Type:

Any ideas?? Thanx
Link to comment
https://forums.phpfreaks.com/topic/4454-mysql-outpt-problem/
Share on other sites

The code looks fine (almost*), although I would use "mysql_fetch_assoc" instead of "mysql_fetch_array".
(*) In the "or die" clause, you have mysql_error, it should be mysql_error().

Dumb question ... is there any data in the database?

You can put a debug print statement in to see what data the script is finding:
[code]<?php
$q = "SELECT * FROM `competitions`";
$result = mysql_query ($q) or die('Problem with query: ' . $q . '<br />' . mysql_error());

while ($row = mysql_fetch_assoc($result)){
     echo '<pre>' . print_r($row, true) . '</pre>';    // debug statement
     $id=$row['ID'];
     $name=$row['name'];
     $races=$row['races'];
     $qualify=$row['qualify'];
     $discards=$row['discards'];
     $type=$row['type'];

     echo "<p><b> " . $name . "</b>" . "<br><i>Races: <b>" . $races . "</b> Number to qualify: <b>" . $qualify . "</b> Discards: <b>" . $discards . "</b> Type: <b>" . $type . "</p></i>";
echo " <a href='$PHP_SELF?deleteme=$id'>Delete Competition</b></a></p>";
}
?>[/code]

Ken
Link to comment
https://forums.phpfreaks.com/topic/4454-mysql-outpt-problem/#findComment-15464
Share on other sites

i did what you suggested to no avail (yes there is something in the database lol!)

But then i used the code you gave me and i got this result (it's the top half you're interessted in):

[img src=\"http://i7.photobucket.com/albums/y254/willwill100/comp.gif\" border=\"0\" alt=\"IPB Image\" /]

where do i go from here?
Link to comment
https://forums.phpfreaks.com/topic/4454-mysql-outpt-problem/#findComment-15476
Share on other sites

[!--quoteo(post=352935:date=Mar 8 2006, 06:55 PM:name=WillWill)--][div class=\'quotetop\']QUOTE(WillWill @ Mar 8 2006, 06:55 PM) [snapback]352935[/snapback][/div][div class=\'quotemain\'][!--quotec--]
where do i go from here?
[/quote]

Looks like your data is getting associaed incorrectly, which means what you have in quotes is wrong :D

Notice how the debug information has "[ Name ] => Topper Main Points" yo're referring to it as

[code]$name=$row['name'];[/code]

when it should be

[code]$name=$row['Name'];[/code]

yes, case does matter. I hope this helped!


Link to comment
https://forums.phpfreaks.com/topic/4454-mysql-outpt-problem/#findComment-15504
Share on other sites

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.