new to php

[new_php]

i know this will look stupid to the rest of you but please bare with me as i am very new to php and programming for that matter.

 

what im trying to do is a little loop within a function that talkes the variable $number and that returns the sum of the numbers between 0 and $number.

 

for example: sum(5) returns 15  since (5 + 4 + 3 + 2 + 1).

 

i've been trying for two days now and i cant seem to get my head wrapped around the solution.

 

any help would be gladly appreciated

 

thank you in advance

[MadTechie]

how about

 

<?php
$t = 5;
echo mysum($t);

function mysum($t)
{
$result = 0;
for ($n=0;$n<$t;$n++)
{
	$result = $result + $n;
}
$result = $result + $n;
return $result;
}
?>

 

hope it makes sence

[kenrbnsn]

Here's an interesting way of doing this, using the range() and array_sum() functions:

<?php
function mysum($n){
$x = range(1,$n);
return(array_sum($x));
}
for ($i=1;$i<10;$i++)
  echo $i.' >>> ' .mysum($i).'<br>'; // just a way of testing it
?>

 

Ken

 

[new_php]

thanks so much for the helps guys!

 

seeing it like this makes much more sense now!

 

 

thanks again!

[monkeymade]

I code differently than most, heres my version, a little shorter...

 

<?PHP
$A = 5;
WHILE ($A != 0)
     {
     $B = $B + $A;
     $A--;
     }
echo $B;
?>

[Barand]

or a condensed version of mad_techie's function

 

<?php

$t = 5;
echo mysum($t);

function mysum($t)
{
for ($n=1, $r=0; $n <= $t; $r+=$n++);
return $r;
}
?>

[MadTechie]

or a condensed version of mad_techie's function

 

Hey no fair is was about 3am when i typed that and i lost sleep over that knowing i should of added the equals

 

LOL