SkyRanger Posted April 20, 2007 Share Posted April 20, 2007 Not sure how to do this. This is what I have: include_once("config.php"); // Check user logged in already: checkLoggedIn("yes"); doCSS(); print("Welcome to the members page <b>".$_SESSION["login"]."</b><br>\n"); print("<a href=\"logout.php"."\">Logout</a>"); I need to figure out some way to add it to this: function main() { php/mysql code here } function board { more php/mysql code here } switch($board) { default: main(); break; case "board"; board($oid); break; } How would I get the top code to work in the functions? I keep getting errors like: Notice: Undefined variable: board Link to comment https://forums.phpfreaks.com/topic/47831-solved-authentication-in-function/ Share on other sites More sharing options...
trq Posted April 20, 2007 Share Posted April 20, 2007 Sorry, but none of that code makes much sense. Link to comment https://forums.phpfreaks.com/topic/47831-solved-authentication-in-function/#findComment-233695 Share on other sites More sharing options...
Moon-Man.net Posted April 20, 2007 Share Posted April 20, 2007 Any variables that are in a function, are just that. Only in the function. unless they are specifically passed to it. to get a variable from out of the function, use this. function test($var){ global $var1 echo $var1 echo $var } I don't need to do it for $var, because it was passed to the function when called. Hope that helps. -- NAthan Link to comment https://forums.phpfreaks.com/topic/47831-solved-authentication-in-function/#findComment-233699 Share on other sites More sharing options...
alecks Posted April 20, 2007 Share Posted April 20, 2007 Umm... not sure what you are trying to do here, but I am guessing that you want to have a forum, and in this forum separate boards. I am going to spell this out as detailed as possible. Ex, the forum structure: YOUR FORUM (1) General (2) Another (3) Another Board If the URL is "index.php", then it would show main(), which is just a listing of these boards. If $oid is set ("index.php?$board=board&oid="), then it would do board($oid), and board() would display the forum board that corresponds to $oid. Ex. If $oid was 1 then based on the example forum structure above board() would display the General forum. Am I right so far? You really don't need the $board variable, based on what I'm seeing. Your code, based on this, may look something like this in the end: include_once("config.php"); function main() { global $whatever_vars_from_config_you_need if (checkLoggedIn("yes")){ doCSS(); print("Welcome to the members page <b>".$_SESSION["login"]."</b><br>\n"); print("<a href=\"logout.php"."\">Logout</a>"); }else{ print("You are not logged in."); } } function board($oid) { // Code to display the board that corresponds with $oid, probably from a database. Also, tests (checkLoggedIn("yes")) to see if they are logged in or not. } switch($board) { default: main(); break; case "board"; board($oid); break; } [/cODE] Sorry if I can't be more help, but you are being pretty vague :/ Link to comment https://forums.phpfreaks.com/topic/47831-solved-authentication-in-function/#findComment-233706 Share on other sites More sharing options...
SkyRanger Posted April 20, 2007 Author Share Posted April 20, 2007 Ok, I will try to explain this a little better. What I am trying to do is: 1) Main PHP Page with Login 2) postit board I am currently working on with is the //code placed on the top of all php pages you want secure include_once("config.php"); // Check user logged in already: checkLoggedIn("yes"); doCSS(); print("Welcome to the members page <b>".$_SESSION["login"]."</b><br>\n"); print("Your password is: <b>".$_SESSION["password"]."</b><br>\n"); print("<a href=\"logout.php"."\">Logout</a>"); When the user logs in they are then sent to for example the page below: office.php which would be http://domain.com/office.php function main(){ $query = "SELECT users.*, office.* FROM users, office where id = omid ORDER BY `oid` DESC"; $result = mysql_query($query) or die ("Query failed"); //let's get the number of rows in our result so we can use it in a for loop $numofrows = mysql_num_rows($result); .... stuff pulled from mysql with a link to ?board=board&oid=".$row['oid']."\"> } function board($oid){ more stuff here pulled from mysql with oid='$oid' } switch($board) { default: main(); break; case "board"; board($oid); break; } This is the config.php file error_reporting(E_ALL); include_once("functions.php"); session_register("login"); session_register("password"); session_register("loggedIn"); $messages=array(); include "inc/dbinfo.inc.php"; $dbhost="$dblocation"; $dbuser="$dbusername"; $dbpass="$dbpassword"; $dbname="$dbname"; connectToDB(); What I need is the top block of code to be inserted somehow into the function main() and function($oid) board and all the other function whatever() that I have in the script. I hope that is a little more clearer on what I am trying to do. Link to comment https://forums.phpfreaks.com/topic/47831-solved-authentication-in-function/#findComment-233708 Share on other sites More sharing options...
SkyRanger Posted April 20, 2007 Author Share Posted April 20, 2007 This was becoming too complicated for myself because I an still a really big noob to php so I decided to separate the file into separate pages till I learn more. Thanks all for all of your help. Link to comment https://forums.phpfreaks.com/topic/47831-solved-authentication-in-function/#findComment-233748 Share on other sites More sharing options...
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