MIR1999 Posted March 14, 2006 Share Posted March 14, 2006 Hello again,Having trouble inserting array values into my database table. The array in question - $qid - is created from values of one table. The form is displayed and when the submit button is pressed i would like the array values to be entered into another table. Here is some of what i have, i have cut irrelevant bits out. I think the problem lies with the fact that when the form is submitted my array values are no longer available so they cannot be inserted. Any ideas?<form name ="systemstest" action="<?php echo $_SERVER['PHP_SELF'];?>"method="post"> <div align="center"><input type="submit" value="check score" name="submitted"></div> <?php //Connect to db. require_once ('../mysql_connect.php'); //Select 10 random questions $query = "SELECT question_id, question, answer, choice1, choice2, choice3 FROM questions ORDER BY RAND() LIMIT 10"; $result = @mysql_query ($query); //Run query if(!isset($_POST['submitted'])){ //display the form $randomiseAnswer=rand(1,5);//used for randomising answer order if($result) { echo '<table align="left" cellspacing="10" cellpadding="10">'; $qid=array(); $counter = 0; while ($row=mysql_fetch_array($result,MYSQL_NUM)){ $id = $row[0]; $qid[$counter] = $id; $questions = $row[1]; $answer = $row[2]; if($randomiseAnswer==1){ $opt1 = $row[3]; $opt2 = $row[4]; $opt3 = $row[5]; } elseif{......}(more choices) //Show questions and random choices(some html/php code) $counter++; }//end while echo '</form>';//close form }else{ //else no result echo'<p>Test failed</p>'; } }else{//Add question ids to database if submitted is pressed require_once ('../mysql_connect.php'); $qu = "INSERT INTO test_score(subject_id, q1,q2,q3,q4,q5,q6,q7,q8,q9,q10) VALUES ('1','qid[0]','qid[1]','qid[2]','qid[3]','qid[4]','qid[5]','qid[6]','qid[7]','qid[8]','qid[9]')"; $res = @mysql_query ($qu);//Run the query } mysql_close(); ?> Quote Link to comment https://forums.phpfreaks.com/topic/4978-problems-inserting-into-db-table/ Share on other sites More sharing options...
hitman6003 Posted March 14, 2006 Share Posted March 14, 2006 Your missing the variable delimiter ($) before your array variable:'[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[0]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[1]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[2]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[3]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[4]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[5]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[6]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[7]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[8]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[9]' Quote Link to comment https://forums.phpfreaks.com/topic/4978-problems-inserting-into-db-table/#findComment-17560 Share on other sites More sharing options...
MIR1999 Posted March 14, 2006 Author Share Posted March 14, 2006 [!--quoteo(post=355090:date=Mar 14 2006, 10:12 PM:name=hitman6003)--][div class=\'quotetop\']QUOTE(hitman6003 @ Mar 14 2006, 10:12 PM) [snapback]355090[/snapback][/div][div class=\'quotemain\'][!--quotec--]Your missing the variable delimiter ($) before your array variable:'[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[0]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[1]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[2]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[3]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[4]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[5]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[6]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[7]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[8]','[!--coloro:#FF0000--][span style=\"color:#FF0000\"][!--/coloro--]$[!--colorc--][/span][!--/colorc--]qid[9]'[/quote]You are correct. However, i've now added them and it makes no difference. There are still no values being added to the table. Quote Link to comment https://forums.phpfreaks.com/topic/4978-problems-inserting-into-db-table/#findComment-17564 Share on other sites More sharing options...
hitman6003 Posted March 14, 2006 Share Posted March 14, 2006 Why are you supressing errors on your query when it's giving you problems?change it to:[code]$res = mysql_query($qu) or die(mysql_error());[/code] Quote Link to comment https://forums.phpfreaks.com/topic/4978-problems-inserting-into-db-table/#findComment-17573 Share on other sites More sharing options...
MIR1999 Posted March 14, 2006 Author Share Posted March 14, 2006 [!--quoteo(post=355103:date=Mar 14 2006, 10:43 PM:name=hitman6003)--][div class=\'quotetop\']QUOTE(hitman6003 @ Mar 14 2006, 10:43 PM) [snapback]355103[/snapback][/div][div class=\'quotemain\'][!--quotec--]Why are you supressing errors on your query when it's giving you problems?change it to:[code]$res = mysql_query($qu) or die(mysql_error());[/code][/quote]Believe me it wasn't intentional. I'm not very good at this lol. Thanks for your quick replies. The error message i get now is:Incorrect integer value:"for column 'q1' at row 1Any ideas? Quote Link to comment https://forums.phpfreaks.com/topic/4978-problems-inserting-into-db-table/#findComment-17576 Share on other sites More sharing options...
hitman6003 Posted March 14, 2006 Share Posted March 14, 2006 [!--quoteo--][div class=\'quotetop\']QUOTE[/div][div class=\'quotemain\'][!--quotec--]Incorrect integer value:"for column 'q1' at row 1[/quote]My guess would be that you are trying to insert an incorrect integer value into the q1 field for your table. Check the data type of that field...if it's supposed to be an INT, then make sure you are trying to insert an INT, if it's not supposed to be an INT, then change it.echo out your query if needed to check that it is correct as well. Quote Link to comment https://forums.phpfreaks.com/topic/4978-problems-inserting-into-db-table/#findComment-17584 Share on other sites More sharing options...
MIR1999 Posted March 15, 2006 Author Share Posted March 15, 2006 [!--quoteo(post=355114:date=Mar 14 2006, 11:04 PM:name=hitman6003)--][div class=\'quotetop\']QUOTE(hitman6003 @ Mar 14 2006, 11:04 PM) [snapback]355114[/snapback][/div][div class=\'quotemain\'][!--quotec--]My guess would be that you are trying to insert an incorrect integer value into the q1 field for your table. Check the data type of that field...if it's supposed to be an INT, then make sure you are trying to insert an INT, if it's not supposed to be an INT, then change it.echo out your query if needed to check that it is correct as well.[/quote]What i've done to test it is to make the initial form display happen only when the button is pressed. I changed if(!isset($_POST['submitted'])){ //display the form to if(isset($_POST['submitted'])){ //display the formso that everything happens only when the button is pressed. I also had to remove the last 'else' so that the database query ran when the button was pressed. When i run it like this it works fine so the correct information is being passed to the array and then onto my table. The problems only start to happen when the array info is passed with if(!isset($_POST['submitted'])) and the last 'else' in place. My array information is not being sent when the submit button is pressed. To get round this i even tried making the insert values like the following:'".$_POST['qid'][0]."' with the 1 changing to a 1 and so on but again i get the Incorrect integer value:"for column 'q1' at row 1 error message. Quote Link to comment https://forums.phpfreaks.com/topic/4978-problems-inserting-into-db-table/#findComment-17611 Share on other sites More sharing options...
MIR1999 Posted March 15, 2006 Author Share Posted March 15, 2006 Ok here's an update. After reading another topic on here about passing variables after a submit button had been pressed i decided i would try and use a session to help with my problem. At the very top of my page i put in<?phpsession_start();?>Then when my while loop had finished and my array had been finalised i put in $_SESSION['questids']=$_POST['qid']Now by my reckoning i have created a new array questids and filled it with the values of qid. Is this correct?Then in my INSERT command held in the 'else' invoked when the button is pressed i have tried various pieces of code e.g.}else{//Add question ids to databaserequire_once ('../mysql_connect.php');$qu = "INSERT INTO test_score(subject_id, q1,q2,q3,q4,q5,q6,q7,q8,q9,q10) VALUES('1','$questids[0]','$questids[1]','$questids[2]','$questids[3]','$questids[4]','$questids[5]','$questids[6]','$questids[7]','$questids[8]','$questids[9]')"; $res = @mysql_query ($qu) or die(mysql_error());//Run the query}mysql_close();I also tried this:}else{//Add question ids to databaserequire_once ('../mysql_connect.php');$qu = "INSERT INTO test_score(subject_id, q1,q2,q3,q4,q5,q6,q7,q8,q9,q10) VALUES('1','".$_SESSION['questids'][0]."','".$_SESSION['questids'][1]."','".$_SESSION['questids'][2]."','".$_SESSION['questids'][3]."','".$_SESSION['questids'][4]."','".$_SESSION['questids'][5]."','".$_SESSION['questids'][6]."','".$_SESSION['questids'][7]."','".$_SESSION['questids'][8]."','".$_SESSION['questids'][9]."')";$res = @mysql_query ($qu) or die(mysql_error());//Run the query}mysql_close();Both continue to give the errorIncorrect integer value:"for column 'q1' at row 1 error message.I can't see where i'm going wrong. Can anyone help? Quote Link to comment https://forums.phpfreaks.com/topic/4978-problems-inserting-into-db-table/#findComment-17761 Share on other sites More sharing options...
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