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[SOLVED] javascript disabling


Ninjakreborn

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I am disabling form fields with javascript.

function start() {
form1.relate.disabled = true;
form1.tl2.disabled = true;
form1.ftn2.disabled = true;
form1.ltn2.disabled = true;
form1.a12.disabled = true;
form1.a22.disabled = true;
form1.tc2.disabled = true;
form1.psc2.disabled = true;
form1.phone2.disabled = true;
form1.email2.disabled = true;
}
// this launches the start function on load.
onload = start;

function enable() {
form1.relate.disabled 	= !form1.activate.checked;
form1.tl2.disabled 		= !form1.activate.checked;
form1.ftn2.disabled 	= !form1.activate.checked;
form1.ltn2.disabled 	= !form1.activate.checked;
form1.a12.disabled 		= !form1.activate.checked;
form1.a22.disabled 		= !form1.activate.checked;
form1.tc2.disabled 		= !form1.activate.checked;
form1.psc2.disabled 	= !form1.activate.checked;
form1.phone2.disabled 	= !form1.activate.checked;
form1.email2.disabled 	= !form1.activate.checked;
}

But it's still passing those fields to the php page even when there disabled, any advice.

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https://forums.phpfreaks.com/topic/50479-solved-javascript-disabling/
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form1.activate is a checkbox?

 

So your page contain a checkbox when user click on it, all the fields will disable/enable based on the checkbox's status?

 

Another question, do you wish to disabled the whole form once user check the box?

 

Consider you say yes, since you have so many fields.

Put this for your javascript:

function disableForm(st){
var the_form = window.document.form1;  //change form1 to your form name
for(var i=0; i<the_form.elements.length; i++){
	the_form.elements[i].disabled = !st;
}
}

 

Put this for your HTML:

<form name="form1" action="testpad.php" method="post">
<input type="text" name="text1" size="15" /><br />
<input type="text" name="text2" size="15" /><br />
<input type="submit" value="Go" />
</form>
<input type="checkbox" name="activate" onclick="disableForm(this.checked);" checked="checked" />

 

This will disable the entire form being post.  ;D

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