how to convert into php format using Regex

[kalyan02]

i would like to convert

 

$teststring = "SESSION[logged=admin]&(GET[id=23]|VAR[page=admin]|POST[pageid!=23])";

into something like this using regex..

"$_SESSION[logged]==admin and ( $_GET[id]==23 or $page=='admin' or $_POST[pageid]!=23 )";

 

please let me know how to do this....as i am not able to figure it out

any help regarding this is appreciated

[MadTechie]

probably like this

 

$test = "SESSION[logged='admin']&(GET[id=23]|VAR[page='admin']|POST[pageid!=23])";
$result = preg_replace('/(SESSION|GET|POST)/i', '$_$1', $test);

[obsidian]

probably like this

 

$result = preg_replace('/(SESSION|GET|POST)/i', '$_$1', $subject);

 

There's a little more to it than that, though, because of the comparison differences, too.

[kalyan02]

but you expression only adds the '$' sign

[obsidian]

Try this, but it may still need some work:

<?php
$string  = "SESSION[logged='admin']&(GET[id=23]|VAR[page='admin']|POST[pageid!=23])";
$pattern = array(
'/(SESSION|GET|POST)\[([^=!\s]+)\s*([=!]+)\s*([^]]+)\]/i',
'/VAR\[([^=!\s]+)\s*([=!]+)\s*([^]]+)\]/i',
'/\s(\=)\s/',
'/([&|]{1})/');
$replace = array(
'\$_$1[$2] $3 $4',
'\$$1 $2 $3',
' == ',
' $1$1 ');

echo preg_replace($pattern, $replace, $string);
?>

 

Hope this helps.

[kalyan02]

it works perfectly

thanks a lot