dtsdave Posted March 15, 2006 Share Posted March 15, 2006 I'm trying to understand why a query on one column will work while a query on another column will not work. I use the following to create a table:[code]CREATE TABLE pages (page_id TINYINT(5) UNSIGNED NOT NULL AUTO_INCREMENT,title VARCHAR(200) NOT NULL,PRIMARY KEY (page_id))[/code]And this is the query I use on a template page:[code]$query = "SELECT * FROM pages WHERE page_id=".$_GET['page_id'];$result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result, MYSQL_ASSOC); [/code]I have some other code on the page to call various data from the row. When I go to sitename.com/template.php?page_id=1 it shows the data I want from the row where page_id=1, sitename.com/template.php?pade_id=2 shows the data I want from the row where page_id=2, etc.Now, I change the query, replacing page_id with title:[code]$query = "SELECT * FROM pages WHERE title=".$_GET['title'];$result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result, MYSQL_ASSOC); [/code]When I go to sitename.com/template.php?title=title1 instead of showing the data from the row where I have a title = title1 I get an error that says Unknown column 'title1' in 'where clause'Where am I going wrong? Thanks in advance for the help. Quote Link to comment Share on other sites More sharing options...
php_b34st Posted March 15, 2006 Share Posted March 15, 2006 I'm not sure if this will solve that problem but i noticed you forgot to close your quotation marks, try:[code]$query = "SELECT * FROM pages WHERE title='$_GET['title']'";[/code] Quote Link to comment Share on other sites More sharing options...
dtsdave Posted March 15, 2006 Author Share Posted March 15, 2006 [!--quoteo(post=355505:date=Mar 15 2006, 05:51 PM:name=php_b34st)--][div class=\'quotetop\']QUOTE(php_b34st @ Mar 15 2006, 05:51 PM) [snapback]355505[/snapback][/div][div class=\'quotemain\'][!--quotec--]I'm not sure if this will solve that problem but i noticed you forgot to close your quotation marks, try:[code]$query = "SELECT * FROM pages WHERE title='$_GET['title']'";[/code][/quote]I don't think that's the problem because when I add the last quotation mark (with either page_id or title) I get a parse error. Quote Link to comment Share on other sites More sharing options...
keeB Posted March 16, 2006 Share Posted March 16, 2006 well, obviously it is taking title1 as your column name..[code]<?php$title = $_GET['title'];$debug = true;$query = "SELECT * FROM pages WHERE title = '$title";if ($debug) print $query;mysql_query($query);?>[/code] Quote Link to comment Share on other sites More sharing options...
dtsdave Posted March 16, 2006 Author Share Posted March 16, 2006 [!--quoteo(post=355528:date=Mar 15 2006, 07:54 PM:name=keeB)--][div class=\'quotetop\']QUOTE(keeB @ Mar 15 2006, 07:54 PM) [snapback]355528[/snapback][/div][div class=\'quotemain\'][!--quotec--]well, obviously it is taking title1 as your column name..[/quote]Why is it taking it as the column name when it doesn't do the same for page_id? Quote Link to comment Share on other sites More sharing options...
dtsdave Posted March 16, 2006 Author Share Posted March 16, 2006 keeB,When I run the code you suggest all I get is the query string spit back at me. Quote Link to comment Share on other sites More sharing options...
keeB Posted March 17, 2006 Share Posted March 17, 2006 Sorry dave.. it looks like i didn't complete it :XAdd that to the bottom.. [=[code]<?php$result = mysql_query($query);while ( $data = mysql_fetch_row ( $result ) ) { print "<pre>"; print_r ( $result ); print "</pre>";}?>[/code] Quote Link to comment Share on other sites More sharing options...
Barand Posted March 17, 2006 Share Posted March 17, 2006 [!--quoteo(post=355536:date=Mar 16 2006, 01:06 AM:name=dtsdave)--][div class=\'quotetop\']QUOTE(dtsdave @ Mar 16 2006, 01:06 AM) [snapback]355536[/snapback][/div][div class=\'quotemain\'][!--quotec--]Why is it taking it as the column name when it doesn't do the same for page_id?[/quote]Because it is a text string value not in quotes. Quote Link to comment Share on other sites More sharing options...
dtsdave Posted March 18, 2006 Author Share Posted March 18, 2006 [!--quoteo(post=355883:date=Mar 17 2006, 05:11 AM:name=Barand)--][div class=\'quotetop\']QUOTE(Barand @ Mar 17 2006, 05:11 AM) [snapback]355883[/snapback][/div][div class=\'quotemain\'][!--quotec--]Because it is a text string value not in quotes.[/quote]Got it! Thank you very much. Quote Link to comment Share on other sites More sharing options...
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