[SOLVED] Parse error: syntax error, unexpected $end in /home/runnerse/public_html/upload2

[runnerjp]

i get the error

Parse error: syntax error, unexpected $end in /home/runnerse/public_html/upload2.php on line 29

 

                      <?
		$db = @mysql_select_db($db_name, $connection) or die("Couldn't select database.");
		$sql = "SELECT * FROM $tbl_images WHERE image_id = $auth[member_id] AND default_pic = \"yes\"";
		$result = @mysql_query($sql,$connection) or die("Couldn't execute query.");
		$PICSnum=mysql_num_rows($result);
		while ($row = mysql_fetch_array($result)) {
		$url = $row['url'];
		$image = $row['image'];
		}
		if(empty($url)) {$newurl="$imgdir";}else{$newurl="$userdir/$url";}
		if(empty($image))$image="pic.gif";
		$showimg="/$newurl/$image";
            ?>
                      <script type="text/javascript">
		function openpopup(popurl){
		var winpops=window.open(popurl,"","width=610px,height=625px,resizable")
		}
                        </script>
                      <p align="center">
             <a href="javascript:openpopup('showpic.php?img=<?echo $image ?>')"><IMG SRC="../../thumbs/phpThumb.php?src=<?echo $showimg ?>&w=150" border="0"></a>
             <?
             if($PICSnum > "0") {
             ?>
             <br>
                                 </p>
                      </td>
                </tr>
            </table>

 

how comes and how do i resolve it? 

 

ty

[paul2463]

you have no closing bracket for your if statement on line 22