cluce Posted May 14, 2007 Share Posted May 14, 2007 I am trying to disable a user from logging in if they have 3 or more failed_ login attempts stored in their record but the code is not displaying my message. Although it still counts the unsuccessful attempts and logs them in with correct username and password. can someomne see where the error is. I would appreciate it. here is my code.... <?php session_start(); //check for required fields from the form if ((!isset($_POST["username"])) || (!isset($_POST["password"]))) { header("Location: user_logon.html"); exit; } //connect to server and select database $mysqli = mysqli_connect("localhost", "root", "", "test"); //create and issue the query $sql = "SELECT username, f_name, l_name FROM auth_users WHERE username = '".$_POST["username"]."' AND password = PASSWORD('".$_POST["password"]."')"; $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); //gets number of unsuccessful logins $attempts = mysqli_query($mysqli,"SELECT failed_logins FROM auth_users WHERE username = '".$_POST["username"]."'"); //checks if user is disabled if ($attempts >= 3){ echo ("login disabled"); } else { //get the number of rows in the result set; should be 1 if a match if (mysqli_num_rows($result) == 1) { //if authorized, get the values of f_name l_name while ($info = mysqli_fetch_array($result)) { $f_name = stripslashes($info['f_name']); $l_name = stripslashes($info['l_name']); } //set authorization cookie setcookie("auth", "1", 0, "/", "yourdomain.com", 0); $_SESSION['usersname'] = $f_name . " " . $l_name; //record last login $sql2 = "UPDATE auth_users SET last_login=NOW() WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli,$sql2); //clears failed logins $sql3 = "UPDATE auth_users SET failed_logins = 0 WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli, $sql3); //directs authorized user header("Location: logon.php"); } else { //redirect back to login form if not authorized $_SESSION['error'] = "<font color='red'>invalid username and/or password combination</font>"; $sql4 = "UPDATE auth_users SET failed_logins = failed_logins + 1 WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli,$sql4); header("Location: user_logon.php"); exit; } } ?> Quote Link to comment Share on other sites More sharing options...
obsidian Posted May 14, 2007 Share Posted May 14, 2007 This is your issue: you are treating the following line as though it is actually returning a value rather then a link resource from your query. You still have to extract the number of attempts from that variable in whatever format you have it stored. <?php // This... $attempts = mysqli_query($mysqli,"SELECT failed_logins FROM auth_users WHERE username = '".$_POST["username"]."'"); // Should be something like this... $sql = mysqli_query($mysqli,"SELECT failed_logins FROM auth_users WHERE username = '".$_POST["username"]."'"); if (mysql_num_rows($sql) == 1) { $attempts = mysql_result($sql, 0, 'failed_logins'); } else { $attempts = 0; } ?> Quote Link to comment Share on other sites More sharing options...
cluce Posted May 14, 2007 Author Share Posted May 14, 2007 now I have these....??? Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, string given in C:\wamp\www\userlogin.php on line 21 Warning: Cannot modify header information - headers already sent by (output started at C:\wamp\www\userlogin.php:21) in C:\wamp\www\userlogin.php on line 63 <?php session_start(); //check for required fields from the form if ((!isset($_POST["username"])) || (!isset($_POST["password"]))) { header("Location: user_logon.html"); exit; } //connect to server and select database $mysqli = mysqli_connect("localhost", "root", "", "test"); //create and issue the query $sql = "SELECT username, f_name, l_name FROM auth_users WHERE username = '".$_POST["username"]."' AND password = PASSWORD('".$_POST["password"]."')"; $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); //gets number of unsuccessful logins // Should be something like this... $sql1 = mysqli_query($mysqli,"SELECT failed_logins FROM auth_users WHERE username = '".$_POST["username"]."'"); if (mysqli_num_rows($sql1) == 1) { $attempts = mysql_result($sql1, 0, 'failed_logins'); } else { $attempts = 0; } //checks if user is disabled if ($attempts >= 3){ echo ("login disabled"); } else { //get the number of rows in the result set; should be 1 if a match if (mysqli_num_rows($result) == 1) { //if authorized, get the values of f_name l_name while ($info = mysqli_fetch_array($result)) { $f_name = stripslashes($info['f_name']); $l_name = stripslashes($info['l_name']); } //set authorization cookie setcookie("auth", "1", 0, "/", "yourdomain.com", 0); $_SESSION['usersname'] = $f_name . " " . $l_name; //record last login $sql2 = "UPDATE auth_users SET last_login=NOW() WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli,$sql2); //clears failed logins $sql3 = "UPDATE auth_users SET failed_logins = 0 WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli, $sql3); //directs authorized user header("Location: logon.php"); } else { //redirect back to login form if not authorized $_SESSION['error'] = "<font color='red'>invalid username and/or password combination</font>"; $sql4 = "UPDATE auth_users SET failed_logins = failed_logins + 1 WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli,$sql4); header("Location: user_logon.php"); exit; } } ?> Quote Link to comment Share on other sites More sharing options...
chigley Posted May 14, 2007 Share Posted May 14, 2007 <?php session_start(); //check for required fields from the form if ((!isset($_POST["username"])) || (!isset($_POST["password"]))) { header("Location: user_logon.html"); exit; } //connect to server and select database $mysqli = mysqli_connect("localhost", "root", "", "test"); //create and issue the query $sql = mysql_query("SELECT username, f_name, l_name FROM auth_users WHERE username = '".$_POST["username"]."' AND password = PASSWORD('".$_POST["password"]."')"); $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); //gets number of unsuccessful logins // Should be something like this... $sql1 = mysqli_query($mysqli,"SELECT failed_logins FROM auth_users WHERE username = '".$_POST["username"]."'"); if (mysqli_num_rows($sql) == 1) { $attempts = mysql_result($sql, 0, 'failed_logins'); } else { $attempts = 0; } //checks if user is disabled if ($attempts >= 3){ echo ("login disabled"); } else { //get the number of rows in the result set; should be 1 if a match if (mysqli_num_rows($result) == 1) { //if authorized, get the values of f_name l_name while ($info = mysqli_fetch_array($result)) { $f_name = stripslashes($info['f_name']); $l_name = stripslashes($info['l_name']); } //set authorization cookie setcookie("auth", "1", 0, "/", "yourdomain.com", 0); $_SESSION['usersname'] = $f_name . " " . $l_name; //record last login $sql2 = "UPDATE auth_users SET last_login=NOW() WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli,$sql2); //clears failed logins $sql3 = "UPDATE auth_users SET failed_logins = 0 WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli, $sql3); //directs authorized user header("Location: logon.php"); } else { //redirect back to login form if not authorized $_SESSION['error'] = "<font color='red'>invalid username and/or password combination</font>"; $sql4 = "UPDATE auth_users SET failed_logins = failed_logins + 1 WHERE username = '".$_POST["username"]."'"; mysqli_query($mysqli,$sql4); header("Location: user_logon.php"); exit; } } ?> Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.