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How will work this script?

 

if the "interpreter_1" is present in dbase print the interpreter_1,

if the "interpreter_2" is present in dbase print the interpreter_2 with a same variable.

 

<?php

$cart_array=array();

 

if($request['interpreter_1']) {

$cart_print[1]=$request['interpreter_1'];

} else {

$cart_print[1]="";

}

 

if($request['interpreter_2']) {

$cart_print[2]="You do it";

} else {

$cart_print[2]="";

}

print $cart_array;

?>

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Sorry, you'll need to be allot clearer in your explanation. You speak of dbase (assumed to be database) but don't show any query.

 

$query_return=mysql_query("SELECT * FROM cart ORDER BY cart_id DESC");

 

while ($request=mysql_fetch_array($query_return)) {

 

$cart_array=array();

 

  if($request['interpreter_1']) {

      $cart_print[1]=$request['interpreter_1'];

  } else {

      $cart_print[1]="";

  }

 

  if($request['interpreter_2']) {

      $cart_print[2]="You do it";

  } else {

      $cart_print[2]="";

  }

print $cart_array;

} // end of while

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https://forums.phpfreaks.com/topic/52095-simple-array/#findComment-256837
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1 ) you can't print an array like that. It will just print "Array". You need print the array elements.

 

foreach ($cart_array as $value) print $value . '<br>';

 

2 ) $cart_array will always be empty as you never put anything in it.

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