[SOLVED] include variable problem

[StuButler]

Hi.

 

I'm new to php and i thought i was being clever and saving myself hassle by using includes for the design of my website. using an include for each section, header, subheader, body and footer.

 

In the pages which use the include and call the design pages (page.php), i have the variables which are added into the designs.

 

For instance, my body_design.php has a variable $bodycontent which loads the content from the variable defined in page.php

 

This all works really well when all im putting in the variable definition is html code and text. It doesn't work if i try and put other php defined variables.

 

I'd like my bodycontent section to show 2 variables, also defined in page.php $var1 and $var2 but i dont know how.

 

I assumed that i would use

 

$bodycontent='<?php echo "$var1 and $var2"; ?>'

 

However this doesn't work (which i assume for anyone with experience is obvious).

 

Can anyone explain how i would do this. I've tried to simplify my situation as the whole thing is quite complex, hope someone can understand what im trying to do.

 

Thanks,

 

StuButler

 

 

[spode]

Concentation.

 

$bodycontent='<?php echo "$var1 . $var2"; ?>'

[StuButler]

Sorry that should have read

 

$bodycontent='<?php echo "$var1" and "$var2"; ?>'

 

using the . just give me a blank space, no actual variables

 

I've added just an echo outside of the designed section and they come up fine so i know the variables are working correctly.

 

Thanks,

 

StuButler

 

[spode]

oh yeah, 

 

for got the ""

[StuButler]

still get a blank space. the page source from my browser is correct:

 

<?php echo "$var1" . "$var2" ?>

 

but it doesnt actually load the variables, just leaves them blank.

 

StuButler

[StuButler]

I think its the echo tag that isnt working properly

 

Can you not use echo tags inside variables?

 

Thanks,

 

StuButler

[spode]

No. I'm pretty sure you'd have to make a function. But I'm just an ewb soo  ???

[corbin]

I'm assuming your page looks like:

 

<?php
$bodycontent='<?php echo "$var1" and "$var2"; ?>';
?>

 

 

My question is.... Why would you reopen PHP?

 

You would just do

 

$bodycontent = $var1 . $var2;

 

Or, if you want some normal text too,

 

$bodycontent = 'This is normal text.... if you put $var here, it will put out \'$var\'.... ' . $var1 . 'this is some more text' . $var2 . "if you use double quotes and put $var1, then $var1 will be replaced with the value of $var1" . $var3 . "If you're wondering why I put \' in the first part, it's because ' has to be escaped when you're using single quotes, or PHP will parse it as if you're ending that string.";

[StuButler]

Thanks, it was indded the double quotations that i was missing.

 

Thanks,

 

StuButler