[SOLVED] how to print a variable variable $GLOBALS array

[dsaba]

here is an array:

$sampleArray_1[] = 'hello';
$sampleArray_1[] = 'world';

 

a function:

$number = 1;
function whatever($num) {
$array = 'sampleArray_'.$num;
print_r($GLOBALS[$$array]);
}
whatever($number);

 

it does not print the $sampleArray

How do I do this correctly? as you can see I am using a dynamic variable name with the variable variable syntax

 

if I do this outside the function:

$num = 1
$array = 'sampleArray'.$num;
print_r($$array);

 

it prints out just fine

 

 

also, if I do this inside the function:

print_r(GLOBALS['sampleArray_1']);

it also prints out fine

 

 

it is doing this variable variable syntax accessing within the function that is causing problems

how do I do it correctly?

 

-thank you

[kenrbnsn]

You're not really using variable variables here, just use the index plain:

<?php
$sampleArray_1[] = 'hello';
$sampleArray_1[] = 'world';

function whatever($num) {
$array = 'sampleArray_'.$num;
echo '<pre>' . print_r($GLOBALS[$array],true) . '</pre>';
}

whatever(1);
?>

 

Ken

[dsaba]

your solution works! thanks

 

 

however you said that I don't need to use variable variables, or that I am not using variable variables??

 

because if you are saying that I am not using variable variables then what do you call this?

$num = 1

$array = 'sampleArray'.$num;

print_r($$array);

 

 

I call that using variable variable syntax, so is that what its called or what?

(ugh... this terminology)

[wildteen88]

no, ken said that you don't need to use variables variables you just use $array as a normal index to the $GLOBALS superglobal.

 

You only need to use $array as a variable variable if you wasn't using the $GLOBALS superglobal.

[dsaba]

tricky tricky wording !

 

hehe I understand now, that's what I thought he said

 

 

Topic Solved!