Preg_Replace $1 <-- Function Parsing

[JustinMs66@hotmail.com]

you know in preg_replace, you can use "(.+?)" and then in the next param, use "$1" well i need to parse that "$1" variable into a function...

see right now it uses it inside the quotes. but when i take it outside the quotes it has errors.

 

it is currently:

"etc $1 etc"

i tried:

"etc " . name($1) . " etc"

but that creates an error, i tried the function inside the quotes.

nothing.

 

any ideas?

[ToonMariner]

if you use preg_match and include the matches parameter then an array will be retruned from the function with all the matches of your regex.