working days?

[ale1981]

Hi,

 

I need to setup a script to run on the FIRST WORKING DAY of each month. I will have the script running as a cron. I was thinking the easiest way of doing this would be to have a bit of php inside the script that detects to see if the day is the first working day of the month and just run the cron every day?

 

Any ideas on how I could script that?

 

 

Any help would be appreciated.

 

 

[Dragen]

you'd probably need an array of the first days, then compare that with the current date.

[ale1981]

Thanks for your reply.

 

Never thought of doing it that way, so I could have an array of all the dates that I want the script to run and check the array to see if the date matches?

 

$go_date = array();

$go_date = '01-01-07', '01-02-07', 01-03-07' ......

 

How would i then search through that array to find if todays day matches it?

 

Thanks again.

[ale1981]

Sorry, searched at  uk.php.net and found my answer;

 

http://uk.php.net/function.in-array

 

Thanks again for your help.

[komquat]

By working day, do you mean Mon- Fri?

 

If so, why not get the day of week from the date function and check that against the first working day.

 

$day_num = date(j);

if ($day_num <= 3) {

$day_name = date(l); //lower case 'L'

  if (($day_name <> Saturday) or ($day_name <> 'Sunday')) {
    
    echo "First Working day";
} else {
    echo "Weekend";
}
}

 

Why not someting like that

[Dragen]

<?php
$go_date = array('01-01-07', '01-02-07', '01-03-07');

if(array_search(date(m-d-y), $go_date) === true){
// todays date is a working day. give it a cookie
}else{
// todays date is not a first working day. bad day!
}
?>

 

something like that.

[ale1981]

By working day, do you mean Mon- Fri?

 

If so, why not get the day of week from the date function and check that against the first working day.

 

$day_num = date(j);

if ($day_num <= 3) {

$day_name = date(l); //lower case 'L'

  if (($day_name <> Saturday) or ($day_name <> 'Sunday')) {
    
    echo "First Working day";
} else {
    echo "Weekend";
}
}

 

Why not someting like that

 

Unfortunately this way would not take into account bank holidays / xmas periods etc?

[ale1981]

<?php
$go_date = array('01-01-07', '01-02-07', '01-03-07');

if(array_search(date(m-d-y), $go_date) === true){
// todays date is a working day. give it a cookie
}else{
// todays date is not a first working day. bad day!
}
?>

 

something like that.

 

I think this is the best way?

 

Here is what I had, does in_array work slower than array_search?

 

$tday = date('d-m');

print($tday);

$workingday = array('03-01','01-02','01-03','02-04','01-05','01-06','02-07','01-08','03-09','01-10','01-11','03-12');

if (in_array($tday, $workingday)) {
echo 'TODAY IS THE FIRST WORKING DAY';
} else {
echo 'TODAY IS NOT THE FIRST WORKING DAY';
}

[Dragen]

does in_array work slower than array_search?

To be honest I don't know what the differende is. They both seem to do the same thing.

 

I think either should work. Your code looks fine.

perhaps someone else could clarify the difference between in_array and array_search?

[GingerRobot]

Well the manul explains it : array_seach returns the key of the value found if it is successful - looks like thats about the only differance. So if you needed to do something with the key or value when you find it, you'd use array_search. If you are simply looking for existance, you'd use in_array.