[SOLVED] dropdown menus and 'if'

[mcas]

I'm trying for 2 days now to create a simple calculator that will display different units(factors) based on selections chosen from a dropdown menu....

 

so, if a user chooses option "a" from the dropdown...the unit factor will be displayed on the next line next to the input box...

and so on if they choose option "b"...

I've tried unsuccessfully $get_mdb=mysql_query("SELECT * FROM mnamedb WHERE unit='$green[0]' ORDER BY id ASC",$link ) or die(mysql_error()); and similar codes...

 

by the way, is there something similar to frontpage for html testing to be found anywhere for php code and display?

[mcas]

if ($_POST[menu]==1) $unit1="selected"; echo'<tr><td

align"left">yes</td>';

 

if ($_POST[menu]==2) $unit2="selected";  echo'<tr><td align"left">no</td>';                                               

echo'<td><input class="inputp" name="'.$m_num.'" type="text" size="5" maxlength="5" value="'.$_POST[$m_num].'"></td></tr>';

 

oops...posted the $get_ instead of where I'm lost...I've tried 'else' in between the 'if' statements and that doesn't work....can someone tell me what I'm missing? In case you cant tell I am a bit of a n00b without my frontapge to show me how it looks and acts..lol

 

Thanks, lostincode (lol)

[corillo181]

what you trying to do is done by javascript.. you want instanly to appear after they choose one?

[mcas]

yes...and can I check javascript somewhere to see it working?

 

[corillo181]

well i dont like java script so i came up with a way to do that with php but it requires for the form to submit over and over again until the last submit bottom is click

 

on your select menu use the onchange="submit();"

 

and set the variable on the top page so when it's submit you get the value so $value next just echo it next to the selection 

[mcas]

ok..Thanks for the advice..