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View Images Code Help


izzytees

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For anyone out there that can solve this, I appreciate it well in advance.  I'm sure it must be something simple, but it has got my head spinning.  I also emailed the author of this code and posted this message on phpbuilder but have yet to hear back so I thought I'd expand my reach to users of this forum.

 

Here is how I'm calling the image page:

<img src="view_image.php?cattype=<?php echo $row_viewimages['cat_type']; ?>&id=<?php echo $row_viewimages['display_id']; ?>"  width="110" height="110" border="0" alt="catalog"/>

 

 

Here are sample issues:

http://www.izzytees.com/viewcatalog.php

http://www.izzytees.com

 

Here is the view_image.php code:

<?php

 

// getdata.php3 - by Florian Dittmer <[email protected]>

// Example php script to demonstrate the direct passing of binary data

// to the user. More infos at http://www.phpbuilder.com

// Syntax: getdata.php3?id=<id>

 

 

if($id) {

 

        $cat = $_REQUEST['cattype'];

        $id = $_REQUEST['id'];

 

 

    // you may have to modify login information for your database server:

    @MYSQL_CONNECT("xxx","xxx","xxx");

    mysql_select_db("xxx");

 

 

    $query = "select bin_data,filetype,display_id,cat_type from image_display where display_id='$id' AND cat_type='$cat'";

    $result = @MYSQL_QUERY($query);

 

 

    $data = @MYSQL_RESULT($result,0,"bin_data");

    $type = @MYSQL_RESULT($result,0,"filetype");

 

 

    Header( "Content-type: $type");

    echo ($data);

 

 

};

?>

 

 

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