plastik77 Posted July 3, 2007 Share Posted July 3, 2007 Hi - apologies if this is a embarrassingly simple query (pretty new to PHP and a newbie to the forums), but if anyone could help that would be appreciated. Basically, I'm creating some test creator software for lecturers at my Uni. I have a Test History page where lecturers can view previous tests they have created (displayed in table format). This is straightforward php/mysql so far, however, I want to be able to hyperlink each test created so that the lecturer can drill into the details of a test if he wants. On clicking a hyperlinked test, a php script will be called which will take the specific test clicked as a GET parameter and will insert it into an SQL query which will return the details of that test on another page. However, I'm not quite sure how to implement this - I realise that I need to use a form in order to pass the parameter to a PHP script, but I don't know to get the hyperlink click to act as a form submission. If anyone can offer any advice that would be great - I've searched numerous forums and haven't found anything on this specific problem. Cheers p.s here is the code as it stands $username = $_SESSION['user']; $query = mysql_query("select * from Test where createdBy = '".$username."'"); $numrows = mysql_num_rows($query); if ($numrows != 0) // If matching lecturer { echo " <table border='1'> <tr> <th>Test Name</th> <th>Date Created</th> </tr>"; for ($i=0;$i<$numrows;$i++) { $row = mysql_fetch_array($query); $name = $row['name']; $date = $row['dateCreated']; $year = substr($date, 0, 4); $month = substr($date, 5, 2); $day = substr($date, 8, 2); echo "<tr>"; echo "<td>".$name."</td>"; echo "<td>".$day."/".$month."/".$year."</td>"; echo "</tr>"; } echo "</table>"; Quote Link to comment Share on other sites More sharing options...
corillo181 Posted July 3, 2007 Share Posted July 3, 2007 how about adding a extra row which says more info about this topic with the topic id attach to it.. so it would be <a hef="whatever.com?$topic_id=123"> and on the next page just search for it. select from table where topic_id=$_GET['topic_id']. Quote Link to comment Share on other sites More sharing options...
HuggieBear Posted July 3, 2007 Share Posted July 3, 2007 If your table named Test has a unique id as a primary key then this shouldn't be too difficult. Just include the id as a GET parameter in the URL. Where you have: echo "<td>".$name."</td>"; Change to this: echo "<td><a href='test_detail.php?test_id=" . $id . "'>" . $name . "</a></td>"; Where I have test_detail.php, change this to the name of your detail page, and where I have $id, change this to the name of the id column in your database. Regards Huggie Quote Link to comment Share on other sites More sharing options...
plastik77 Posted July 3, 2007 Author Share Posted July 3, 2007 thanks for both replies - that makes perfect sense and each test has a unique id so that part is straightforward the main thing i had trouble understanding was how to actually submit the form to call the script without using a submit button - but by adding the item id into the url, that allows me to GET the test ID from the url cheers for your time! Quote Link to comment Share on other sites More sharing options...
HuggieBear Posted July 3, 2007 Share Posted July 3, 2007 That's right, then it's as easy as using $_GET['test_id'] in the page being called. Don't forget to use the solved button to mark this topic as solved. Regards Huggie Quote Link to comment Share on other sites More sharing options...
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