[SOLVED] How to calculate the day of the week by a given date.

[Anzeo]

Hi all, finally back to coding.

 

I've advanced quite a bit with my current project, but the time has come again I can't code my way any further.

 

I'm currently working on a (simple) calendar system which allows registered users to add an event to the calendar. The table EVENT stores info about the author, date and description of the event.

 

I then managed to output a list in which only events of this year are showed and are grouped together by months.

 

And now I only need one more thing to complete the script. I want to output for every event on which day of the week it occurs (monday - sunday). I've looked around for tutorials but haven't found a basic one.

 

Does anyone know how to accomplish this? Many thanks in advance!

[Jewbilee]

if you know the number month, the number day, and the number year:

 

echo date("l", mktime(0, 0, 0, $month, $day, year));

[AndyB]

Just to add to that ...

 

http://www.php.net/manual/en/function.date.php

http://www.php.net/manual/en/function.mktime.php

[Anzeo]

Works great, thanks a lot! Is their a quick way to translate the result to dutch?

[AndyB]

http://www.php.net/manual/en/function.setlocale.php - the very first example

[Anzeo]

The setlocal doesn't seem to be working. I assume I'll have to use a switch or something like that to translate 'manually' ?

 

I read somewhere that the language file has to be installed on the server in order for setlocal to be working?

[Barand]

date('w') returns 0-6 (sun-sat) so you could use use an array of daynames if all else fails

[Anzeo]

But when using the date function, I can't use a given specified date as the argument or can I?

[Barand]

You have already seen that you can do that in an earlier post. I was just suggesting "w" instead of "l" and using an array such as this (only translated into Dutch equivalents)

 

<?php
$days = array('Sunday', 'Monday', 'Tuesday','Wednesday', 'Thursday', 'Friday', 'Saturday');
$dow = date('w', strtotime('2007-07-07'));
echo $days[$dow];  // Saturday
?>

[Anzeo]

Thanks everyone got it working ^^!

 

I'm going to study more on the date functions .