[SOLVED] session

[bhavin12300]

hi

in my website i want to show all the member who are signin  in my website.like it will sow all the member who whose session are on.

 

how to do that?

 

 

[pocobueno1388]

I don't think you can tell which sessions are active or not, at least not with PHP. Here is how I would go about it.

 

• Make a column in the users table called "last_active".
  
• Every time the user clicks, update that column in the table to the current time with a timestamp.
  
• On the page where you are showing the users online, just select all the users from the database where the last_active field is X minutes old, which will select the users that have currently been active.

[teng84]

i havent done something like that but if im going to do that then i will do this

 

when the user log get the information od him and set on the table like active then he leaves set in active

how ?

when the user logged update the table in your db for that person set as active then before he logout or once he logged out set your table field like in active

[pocobueno1388]

i havent done something like that but if im going to do that then i will do this

 

when the user log get the information od him and set on the table like active then he leaves set in active

how ?

when the user logged update the table in your db for that person set as active then before he logout or once he logged out set your table field like in active

 

You can't rely on the user to press "logout" all the time, so your method would be unreliable.

[bhavin12300]

thansk you i got your answer . i will do that.

 

that user x minute old.cool logic

oce again thank you

[teng84]

i havent done something like that but if im going to do that then i will do this

 

when the user log get the information od him and set on the table like active then he leaves set in active

how ?

when the user logged update the table in your db for that person set as active then before he logout or once he logged out set your table field like in active

 

You can't rely on the user to press "logout" all the time, so your method would be unreliable.

 

yes i know dude i only giving here an idea if  i were to do that ill do an option on my code like before he leave ill put a pop up screen like sure you want to logout

look some of the members here aren't knowledgeable enough so giving then all of this stuff

will make there nose bleed