[SOLVED] logic help

[lc21]

I am developing a log for problems recorded with a system and I have these problems being output to a table within a form and each record has a radio button for the user to select.

 

they are being output as in the code below:

 

<?php
while($display=mysql_fetch_array($query))
{
     echo "<tr><td>".$display['problemId']."</td><td>".$display['name']."</td></tr>";
}
?>

 

How do I get the unique identifer (problemId) to be chosen when the user selects the appropreate radio button? as problems can be added and removed all the time.

 

Thanks.

[nloding]

If I understand what you're asking ... you're going to need to do a query based on the value of the radio button.  So if the radio button is named "problem" or something ...

 

SELECT * FROM table WHERE problemid=$_POST[problem]

 

Or something like that.

[dbillings]

<form method="post" action="<?php $_SERVER['PHP_SELF']; ?>">

 

<?php

while($display=mysql_fetch_array($query))

{

    echo "<tr><td>".$display['problemId']."</td><td>".$display['name']."</td>

              <td><input type=\"radio\" name=\"problemId\" value=\"$display\"></td></tr>";

}

?>

<tr>

  <td>

    <input type="submit" value="Submit">

    < /form>

  </td>

</tr>

[lc21]

 

<td><input type=\"radio\" name=\"problemId\" value=\"$display\"></td></tr>";

 

In the value aspect of this line of code what would be displayed is it the first element of the array and if so how do you display the other elements? Thank you

[trq]

$display is an associative array... so somthing like...

 

<td><input type=\"radio\" name=\"problemId\" value=\"{$display['fieldname']}\"></td></tr>";

 

would be the correct way to display it.

[lc21]

Thanks I am having a hard time learning all the syntax I always end up getting my " " or ' ' mixed up.