[SOLVED] String insertion and extraction

[otuatail]

is there a function to replace  a section af a string with another regardless of the values and to do the reverse i.e.

 

$srt1 = "ABCDEFGHIJKLM")

$str2 = "XY

 

// insert $str2 in to $str1 [3] and [4]

$srt1 = "ABCXYFGHIJKLM")

AND

$str = $str1 positions [7] and [8]

$str = "HI";

 

I want to do some incripion on text. OR will I have to create something?

 

Desmond.

 

[trq]

This may help as an example...

 

<?php

  $s = 'abcdefg';
  $s[1] = 'x';
  $s[2] = 'y';
  echo $s;

?>

[jd2007]

$srt1 = "ABCDEFGHIJKLM";
$str2 = "XY";
$char1=str_split($srt1);
$char2=str_split($srt2);
$char1[2]=$char2[0];
$char1[3]=$char2[1];
$srt1=join("", $char1);
$char3=str_split($srt1);
$str=$char3[7].$char3[8];

 

let me explain the above . u have two strings $srt1 and $str2. u want to place $str2 in $srt1 at positions where C and D is now currently. so, u split $srt1 into an array called $char1. note that the first element starts with 0 not 1, so $char1[0] is A. Now, you split $str2 into an array also called $char2. Now, $char2[0] is X and $char2[1] is Y. now, u want to replace C with $char2[0]. C is $char1[2]. in other words, u want to replace $char2[0] with $char1[2]. So, u assign $char2[0]'s value into $char1[2]. now, u want to replace D with $char2[1]. D is $char1[3]. in other words, u want to replace $char2[1] with $char1[3]. So, u assign $char2[1]'s value into $char1[3]. now, $char1[2] is X and $char1[3] is Y. now, u would need to join all elements to form this string: $srt1 = "ABCXYFGHIJKLM". so, use the join function :  join("", $char1);...go here to see info about the join() function...http://www.w3schools.com/php/func_string_join.asp.

now, u want H and I from $srt1 and place them in $str like this $str="HI". so, u split $srt1 into $char3...$char3[7] and $char[8] is H and I. u concetenate them in a string $str...check this sites out www.w3schools.com and www.php.net/manual

[otuatail]

Ok thanks that works but if I say

$line = time();

$line[5] = "0";

 

Cannot use a scalar value as an array

 

Need to convert this to a standard string.

 

Desmond.

 

[otuatail]

Sorry what thorpe said worked without splitting. A for() loop works but only if It is a string.

time(); and rand() don't because they are treated as numbers now not strings.

 

 

[otuatail]

Thanks Guys  This seems to work.

 

$p = time();

$p = "1" . $p  // Force it to a string value

$p[3] = "5"  // works now.

 

Thanks.