[SOLVED] Log in script

[fesan]

Hi there.

 

I have a very simple php login script on my page. just to have some security on some pages.

 

The login works fine, it logs in and displays the password required pages as they should.

But I am adding a script that enables a menu that is invisible to normal users. but it is always shown.

It seams i cant log out. I know this has worked before. Can anyone help me to find the bugs?

 

So in the end of the login proses it makes these variables:

session_start();
$_SESSION["login"] = true;
$_SESSION["user"] = $usr;
$_SESSION["status"] = $status;

 

 

in top of my index page i have this code:

session_start();
if(isset($_GET['logut'])) {
$_SESSION['login'] = false;
unset($_SESSION["user"]);
unset($_SESSION["status"]);
}

 

 

and on the pages required by index.php that needs password, this code is on top:

session_start();
if(empty($_SESSION['login'])) {
echo "You are not logged in";
} else { ?> 
HTML
<?php } ?>

 

my admin menu looks like this for testing reasons:

<?php
if ($_SESSION['login'] = true){
if ($_SESSION["status"] = "a"){
echo "<div id='admin'>";
echo $_SESSION['login']. "<br>";
echo $_SESSION['logout']. "<br>";
echo $_SESSION['usr']. "<br>";
echo $_SESSION["status"];
echo "</div>";
}
}?>

 

The results for:

login = 1

logout =

usr =

status = a

 

My logout link looks like this:

<a href='index.php?logut=true'>Log out</a>

 

Thanks for any help!!!

[Fadion]

didnt look very carefully to the code but i did notice this line:

 

if ($_SESSION['login'] = true){

 

You are initializing it, not comparing. Intending to compare you must use identical operator '=='.

 

if ($_SESSION['login'] == true){

[fesan]

Thats was quite easy..... Stupid mistake by me!

 

It worked perfektly now! Sorry for the truble!

 

Thank you very much!!!