joshgarrod Posted July 27, 2007 Share Posted July 27, 2007 Hello everyone, I have a script which searches a table of stock and brings back results dependant upon the search term that was used. I have put a URL of a page that explains further about the stock item, however I cannot get it to display as a link. Can somebody take a look please? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Search for spares</title> <style type="text/css"> <!-- .style1 {font-family: Arial, Helvetica, sans-serif} --> </style> </head> <body> <h2 class="style1">Search</h2> <form action="<?=$PHP_SELF?>" method="post" name="search" class="style1"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="Make" selected="selected">Make</option> <Option VALUE="Model">Model</option> <Option VALUE="Engine">Engine</option> <Option VALUE="Berth">Berth</option> <Option VALUE="Year">Year</option> </Select> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <p class="style1"> <?php $find = $_POST['find']; //This is only displayed if they have submitted the form if ($searching =="yes") { echo "<h2>Results</h2><hr>"; //If they did not enter a search term we give them an error if ($find == "") { echo "<p>Please enter a search term"; exit; } // Otherwise we connect to our Database mysql_connect("localhost", "sto21", "ixhp388") or die(mysql_error()); mysql_select_db("sto21") or die(mysql_error()); // We preform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); //Now we search for our search term, in the field the user specified $find_array = explode(" ", $find); $find_sql = ""; // init foreach ($find_array as $temp) $find_sql .= "upper($field) LIKE '%".$temp."%' OR"; // note only need to do the substr once, the second time was removing the other %' $find_sql = substr($find_sql, 0, -3); // throw away last OR statement $sql = "SELECT * FROM motorhomes WHERE $find_sql"; $data = mysql_query($sql) OR DIE("SQL Was: " . $sql . "<br />ERROR: " . mysql_error()); $sql = mysql_query("SELECT * FROM motorhomes"); $num = mysql_num_rows($sql); if ($num > 0) { // There's a result } else { // No results found. }//And we display the results while($result = mysql_fetch_array( $data )) { echo "<b>Motorhome ID: </b>"; echo $result['MhID']; echo "<br>"; echo "<b>Make: </b>"; echo $result['Make']; echo "<br>"; echo "<b>Model: </b>"; echo $result['Model']; echo "<br>"; echo "<b>URL - Click here to view more details: </b>";//this line and the line below is where I am trying to display the URL, the URL is very long I would just like the link text to say "more details" if possible. echo "<a href=\"$results[url]\">URL</a>"; echo "<br>"; echo "<hr>"; } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches=mysql_num_rows($data); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> </p> </body> </html> Quote Link to comment Share on other sites More sharing options...
Daniel0 Posted July 27, 2007 Share Posted July 27, 2007 Try to change echo "<a href=\"$results[url]\">URL</a>"; to echo "<a href=\"{$results['URL']}\">URL</a>"; Quote Link to comment Share on other sites More sharing options...
Lumio Posted July 27, 2007 Share Posted July 27, 2007 damn I'm to slow... you can also use echo "<a href=\"".$results['URL']."\">URL</a>"; Quote Link to comment Share on other sites More sharing options...
joshgarrod Posted July 27, 2007 Author Share Posted July 27, 2007 This displays a link however, the link just goes back to the homepage? Quote Link to comment Share on other sites More sharing options...
Daniel0 Posted July 27, 2007 Share Posted July 27, 2007 Well, it should display the link you have in your database. Quote Link to comment Share on other sites More sharing options...
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