[SOLVED] show error message on same page

[Daryl B]

Hi Guys,

 

I have Index.php which contains the HTML form with a username and password field + submit button, action: is my check.php.

 

Say for example the user only input's a username and miss out the password field; when he clicks the submit button. I want the same page to be refreshed with a error message appearing below the submit button saying "error, please fill all in". I can get this to display on another page. but want this to be on refereshed on the log-in page.

 

If anyone can help that would be great.

 

Thanks ???

[zq29]

Post your form back to itself and do all of your error checking in the same script file.

[Goose87]

yeah, what i do is this:

if (isset($_POST['submit'])) {  // Check if the form has been submitted.

require_once ('connect.php');  // Connect to the database

if (empty($_POST['username'])) {  // Validate the username.
	$u = FALSE;
	echo '<p>You forgot to enter your username!</p>';
} else {
	$u = ($_POST['username']);
}

if (empty($_POST['password'])) { // Validate the password.
	$p = FALSE;
	echo '<p>You forgot to enter your password!</p>';
} else {
	$p = ($_POST['password']);
}

if ($u && $p) { // Everything is ok.

 

This checks that the fields have been entered before it checks if the username and password are correct.

 

Then after that i query the database, and then i end the php and have the html form.

 

Hope that helps, if not, i can give you my whole index script which will achieve what you want.

[Daryl B]

cheers guys. I will give this a go and let you know how i get on.

 

Looks good though

[Daryl B]

Hey,

 

cant seem to get it working:

 

this is my code:

 

<?php
session_start();
include('db.php');

if(isset($_POST['submit'])) : // Check if the form has been submitted.
// Username and password sent from signup form
// First we remove all HTML-tags and PHP-tags, then we create a sha1-hash

$username = strip_tags($_POST['username']);
$password = sha1(strip_tags($_POST['password']));

// Make the query a wee-bit safer
$query = sprintf("SELECT ID FROM members WHERE username = '%s' AND password = '%s' LIMIT 1;", mysql_real_escape_string($username), mysql_real_escape_string($password));

$result = mysql_query($query);
if(1 != mysql_num_rows($result)) :
	// MySQL returned zero rows (or there's something wrong with the query)
	header('Location: index.php?msg=login_failed');
else :
	// We found the row that we were looking for
	$row = mysql_fetch_assoc($result);

	// Register the user ID for further use
	$_SESSION['member_ID'] = $row['ID'];
	header('Location: members-only.php');
endif;
endif;

if( ($username == null) or ($password == null) )
{header("location:index.php"); exit();}
?>

 

Edited by SA: Please use the [code][/code] tags!

[zq29]

What do you mean by "cant seem to get it working"? What's it (not) doing?

 

Side note: I didn't know that was valid syntax for if constructs in PHP, couldn't find anything in the manual - Where did you learn to use them that way?!

[Daryl B]

Regarding the if constructs in PHP: I have just learnt myself using Mike McGeth's PHP5 book and the net. It must be a valid syntax as it does work.

 

Which part of the code did pick up on the syntax issue?

 

I have sorted the orginal issue, thanks. You post helped.