jd2007 Posted July 30, 2007 Share Posted July 30, 2007 <?php include("connect.php"); if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; $songt=$_GET[u]."songs"; $query="insert into $songt(name, artist) values ($_POST[name], $_POST[artist])"; $result=mysql_query($query); } } ?> i get output: Return Code 1... i file i try to upload is C:\Documents and Settings\oem\My Documents\My Music\Train-Drops_of_Jupiter.mp3 Quote Link to comment Share on other sites More sharing options...
Fadion Posted July 30, 2007 Share Posted July 30, 2007 I dont get this query: $query="insert into $songt(name, artist) values ($_POST[name], $_POST[artist])"; Shouldnt it be: $query="insert into table (name, artist) values ('{$_POST['name']}', '{$_POST['artist'])}'"; Quote Link to comment Share on other sites More sharing options...
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