2tonejoe Posted July 30, 2007 Share Posted July 30, 2007 here is the code: <?php include('/Library/WebServer/Documents/scripts/db-connnect.php'); $username = $_POST['name']; $userfacility = $_POST['facility']; $userposition = $_POST['position']; $useremail = $_POST['email']; $usercontact = $_POST['contact']; $userpass = $_POST['pass1']; $id = $_POST['userid']; $query = "UPDATE `addison`.`users` SET `user_name` = '$username',`user_facility` = '$userfacility',`user_position` = '$userposition',`user_email` = '$useremail',`user_contact` = '$usercontact',`user_pass` = '$userpass',`update_date` = NOW( ) WHERE `users`.`user_id` ='$id' LIMIT 1 ;"; mysql_select_db('addison'); $check = mysql_query("SELECT user_name FROM users WHERE user_name = '$username'") or die ("query 1: " . mysql_error()); $mysql_num = mysql_num_rows($check); if ($mysql_num != 1) { echo "<br /><br /><br /><h2><center>I can't add <b>".$username."</b> because this person is already a user.</h2></center>\n"; echo '<br /><h4><center>Please use the <a href="http://mysite.com/index.php?page=update-a-user">User Update Form</a> or simply <a href="' . $_SERVER['HTTP_REFERER'] . '">Retry</a> it.</h4></center>'; } else { mysql_query( $query); echo "<br><br><center><h2>The user <b>".$username."</b> was added succesfully!</h2></center>\n"; echo '<br /><center><h4><a href="' . $_SERVER['HTTP_REFERER'] . '">Go Back</a></center></h4>'; } mysql_close($mysql_link); ?> I even used phpMyAdmin to generate the query this time. It doesn't error but it doesn't update anything. If i change this to an insert. . .it will work . . ???? What am I doing wrong? Quote Link to comment https://forums.phpfreaks.com/topic/62493-update-just-not-working/ Share on other sites More sharing options...
trq Posted July 30, 2007 Share Posted July 30, 2007 mysql_query( $query) or die(mysql_error()); Now do you get an error? Quote Link to comment https://forums.phpfreaks.com/topic/62493-update-just-not-working/#findComment-311055 Share on other sites More sharing options...
pikemsu28 Posted July 30, 2007 Share Posted July 30, 2007 are you creating accounts? this looks like an account creation page since you are querying the user table to check to see if the username already exists. if this is an account creation page, then you need to use INSERT instead of UPDATE. there has to be a record that already exists to update it. EDIT: plus you need to add the code thorpe suggested. Quote Link to comment https://forums.phpfreaks.com/topic/62493-update-just-not-working/#findComment-311058 Share on other sites More sharing options...
2tonejoe Posted July 30, 2007 Author Share Posted July 30, 2007 mysql_query( $query) or die(mysql_error()); Now do you get an error? nope. no error. also, this is a user creation thing . .well its an edit page. I have the information thrown into a form. this is the page that sends to the script: <?php include('/Library/WebServer/Documents/scripts/db-connnect.php'); mysql_select_db("addison") or die(mysql_error()); $id = $_GET['id']; $query = mysql_query("SELECT * FROM users WHERE user_id='$id'"); $values = mysql_fetch_array($query); echo "<table style=\"width: 800px; height: 98px; text-align: left; margin-left: auto; margin-right: auto;\" border=\"0\" cellpadding=\"2\" cellspacing=\"2\">"; echo "<tr><td>"; echo "<fieldset><legend>Edit ".$values['user_name']."</legend>"; echo "<form name=\"userinfo\" enctype=\"multipart/form-data\" action=\"/scripts/update-a-user.php\" method=\"POST\">"; echo "<br> "; echo "<input name=\"name\" value=\"".$values['user_name']."\"> Full Name<br>"; echo "<br> "; echo "<select selected=\"".$values['user_facility']."\" name=\"facility\">"; echo "<option>Chesapeake</option>"; echo "<option>Fort Worth</option>"; echo "<option>Ontario</option>"; echo "<option>Providence</option>"; echo "</select> Composing Facility<br>"; echo "<br> "; echo "<select selected=\"".$values['user_position']."\" name=\"position\">"; echo "<option>Book Builder</option>"; echo "<option>Ad Builder</option>"; echo "<option>Proofer</option>"; echo "<option>Trafficker</option>"; echo "<option>Typesetter</option>"; echo "<option>Shift Manager</option>"; echo "<option>Customer Serivce</option>"; echo "<option>Office Manager</option>"; echo "<option>Composing Manager</option>"; echo "</select> Position<br>"; echo "<br> "; echo "<input name=\"email\" value=\"".$values['user_email']."\"> Email Address<br>"; echo "<br> "; echo "<input name=\"contact\" value=\"".$values['user_contact']."\"> Contact Number<br>"; echo "<br> "; echo "<input name=\"pass1\" value=\"".$values['user_password']."\"> Password<br>"; echo "<br> "; echo "<input name=\"userid\" disabled value=\"".$id."\"> Addison ID Number<br>"; echo "<br> "; echo "<input value=\"Add\" type=\"submit\"> <input value=\"Clear Form\" type=\"reset\"><br><br>"; echo "</fieldset><br><br>"; echo "</form>"; echo "</td></tr>"; echo "</table>"; mysql_close($mysql_link); ?> Quote Link to comment https://forums.phpfreaks.com/topic/62493-update-just-not-working/#findComment-311072 Share on other sites More sharing options...
2tonejoe Posted July 30, 2007 Author Share Posted July 30, 2007 should I be doing this in another way? I just wanted to check and see if the user exists. . and if he/she does then update it. . . . I am so frustrated that it doesn't work . . . i dont know what is wrong. Quote Link to comment https://forums.phpfreaks.com/topic/62493-update-just-not-working/#findComment-311085 Share on other sites More sharing options...
2tonejoe Posted July 31, 2007 Author Share Posted July 31, 2007 bump Quote Link to comment https://forums.phpfreaks.com/topic/62493-update-just-not-working/#findComment-311645 Share on other sites More sharing options...
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