[SOLVED] PHP error, variables

[Foser]

<?php 
$list_query = mysql_query("SELECT * FROM item_info");

echo "<table width=\"200\" border=\"1\"><tr><th scope=\"col\">ID</th><th scope=\"col\">Name</th> <th scope=\"col\">Author</th><th scope=\"col\">Manage</th>";   
while ($item_list = mysql_fetch_assoc($list_query)){
echo '<tr><th scope=\"col\">$item_list[item_id]</th> <th scope=\"col\">$item_list[item_name]</th><th scope=\"col\">$item_list[item_author]</th><th scope=\"col\"><a href=\"manage_item.php?item=$item_list[item_id]\">Manage</a></th>';
}?>

 

When it outputs i all i see is the $item_list[item_id] and not the actual id...

 

I also tried with {$variable}... but still didnt work

[Daniel0]

Use double quotes and put curly brackets around the variables. That is needed when you are using arrays.

 

Variables will only be parsed when enclosed in double quotes.

 

Edit: You should also use single or double quotes around the array keys. Else you are using constants which is not what you intended.

 

Edit 2: Without curly brackets is called simple syntax and with is called complex syntax (see http://php.net/string)