php echo two html tables side by side.

[sayedsohail]

Hi everyone, I am trying to print two html tables side by side, one table will have 2-4 columns and values from mysql_query, and the second table will just display few small icons.   The reaon i am trying this, so i can link two separate tr onlick events.

 

table 1               table 2

--------------|------------

echo'$name';  | <INPUT type='button' value='edit'>

.                 

.

.

.

--------------|------------

 

here is my code which works perfectly fine to display records horizontally, but i want to display as above.

 

$result = mysql_query($sql); 
$display = 2; 
$cols = 0; 
echo "<table>"; 
while($fetched = mysql_fetch_array($result)){ 
   if($cols == 0){ 
       echo "<tr>\n"; 
   } 
   // put what you would like to display within each cell here, 
if you noticed at the moment i am able to display button side by side for the record,
but i want to display this in the iind table side by side.

   echo "<td>".$fetched['id']."<br />".$fetched['name']."</td><td><input type='button' value='Delete'></td><td>Insert</td><td>Print</td>\n"; 
   $cols++; 
   if($cols == $display){ 
       echo "</tr>\n"; 
       $cols = 0; 
   } 
} 
// added the following so it would display the correct html 
if($cols != $display && $cols != 0){ 
   $neededtds = $display - $cols; 
   for($i=0;$i<$neededtds;$i++){ 
       echo "<td></td>\n"; 
   } 
     echo "</tr></table>"; 
   } else { 
   echo "</table>"; 
} 

 

Any suggestions is greatly apprecaited.

 

Thanks

   

 

 

[ss32]

use the colgroup tag; it has the onClick event that you are looking for.  it will make things SO much easier than echoing two tables

[sayedsohail]

This is what i am trying to achieve, but onlick and onmouseover non of the functions are working?

 

print "<tr ><COLGROUP name=\"high\" onmouseover=\"flyOver(this)\" onmouseout=\"flyOut(this)\"

onclick=\"selectMe(this);\">";

print "<td> $Service_Summary</td><td>$name</td></COLGROUP>";

print "<td>Delete</td><td>Insert</td></tr>";