[SOLVED] another unexpected $end

[Styles2304]

ok, I'm trying to make a session deal for user authentication . . . it constantly returns invalid user name and/or password.

 

Just to check what it's returning I did this:

 

<?php
//Starting the session and user authentication
session_start();
include "conn.inc.php";

if (isset($_POST['submit'])) {
  $query = "SELECT Username, Password FROM UserInfo " .
           "WHERE Username = '" . $_POST['username'] . "' " .
           "AND Password = (PASSWORD('" . $_POST['password'] . "'))";
  $result = mysql_query($query,$link)
    or die(mysql_error());
?>

<?php
echo $result;
?>

 

It gives me:

 

Parse error: syntax error, unexpected $end in /home/styles/public_html/login.php on line 16

which is the "?>"

 

I know it's syntax but I don't know what I'm doing wrong.

[Gho§t]

You forgot to close that "if" statement.

[uwannadonkey]

if (isset($_POST['submit'])) {

  $query = "SELECT Username, Password FROM UserInfo " .

          "WHERE Username = '" . $_POST['username'] . "' " .

          "AND Password = (PASSWORD('" . $_POST['password'] . "'))";

  $result = mysql_query($query,$link)

    or die(mysql_error());

}

?>

 

for the record, when you forget a curly, it runs code till end of page, meaning error is on last line, even if it isnt

[Styles2304]

ahhh I see, learn something new every day! Thanks!