how can I get PHP displays parsing error and line number

[hvle]

I know I got syntax error some where.  But php simply say "Errors parsing esearch.php".  It does not display line number or any kind of hint.  I've also set the error reporting to display all error and E_PARSE in ph.ini

 

I am using php 5.2 and command line to run.

 

Thanks

[uwannadonkey]

post the code?

 

have u tried a debugger?

[hvle]

well I found the syntax, but that's not problem.  I need php to display the line number that has the parsing error to make debugging quicker. 

[uwannadonkey]

have u tried a debugger?

[hvle]

have u tried a debugger?

 

I don't aware there is one.  How do I get one?

[uwannadonkey]

google is ur best friend, mate!

 

<a href=http://www.google.com/search?hl=en&q=php+debugger&btnG=Search>Google Search Link(click here, i searched for you!)</a>

[hvle]

thanks

[uwannadonkey]

marks us solved!

 

*Click solved button!*

 

have a nice day!

[hvle]

um.. its not solved.  Debugger doesn't work!

 

Still looking for a configuration in PHP that display parsing error information

[uwannadonkey]

did u link your debugger to your php path?

[hvle]

I loaded the debugger as php module in php.ini

[hitman6003]

set error reporting to all:

 

error_reporting(E_ALL);

 

ensure display errors is on:

 

ini_set("display_errors", 1);

 

I think that you can also use __LINE__ to display the line in the php file.

 

http://us2.php.net/manual/en/language.constants.predefined.php

[hvle]

The thing that troubled me is the parsing error, not run-time error.  The error occurs when php see a php code that it doesn't like.

 

try to run a code like this

<?php
for ($i=1;$i<5; $i++)
{
  $i = 6
}
?>

 

Note there is no semicolon after 6.  When running this script, I got absolutely error message.

except for "parsing error".

 

[dbo]

Did you follow hitmans suggestion?

[hvle]

yes I did,

 

This is the code:

<?php
ini_set("display_errors", 1);
error_reporting(8191);


echo "alskdjfalskdfj";

for ($i=1;$i<5; $i++)
{
  $i = 5

}

?>

 

[dbo]

That's some good looking code! What output is it producing now? Is there anyway you can slap it on Apache and let us point a browser at it and see what it says?

[hvle]

That's just a test code that should produce some parsing error.

The command line out put when I ran that code:

 

in Unknown on line 0

[dbo]

Oh I agree it should produce an error. Interestingly enough I've never used PHP as just a scripting language from the command line. I've only used it for web stuff. In theory I guess it should be the same. Hrmmm.

[dbo]

Yeah I dunno. Logically that should work according to the manual http://us3.php.net/error_reporting

[hvle]

imagine you got that error somewhere in a 4,000 line of code script.  It won't be pretty.

[dbo]

Absolutely agree.