[SOLVED] Dilemna with Arrays

[Roybot06]

Okay I am creating an page using a .php array to randomize a few ads on the page. Every time it is refreshed it will either mix the three ads on the page or throw in another one. I had the idea of linking these pictures to their respective sites, but if I used an anchor tag out side the :

print "<a href=\"#"><img src=\"images/".$ad_array[0]."_120x60.jpg\"></a><br><br>\n";

 

It will give me a fixed link, but I won't have a way of having the link move with the randomizing of the pictures. I was thinking on the lines of creating another array to move with the random pictures.

 

I have the array set to present a word in front of the picture extension (i.e., "red" in the array will make the picture red_120x60.jpg, etc.) , and the array's code:

 

$ad_array = array("red", "green", "blue", "magenta");

 

Does anyone have any suggestions, or can they tell me if what I'm thinking of is possible?

 

Either one will be greatly valued.

 

Thanks

 

 

 

[willpower]

you need to use multidimensional arrays

 

this is where each array key has another set of keys and values attached.

 

see http://www.desilva.biz/arrays/multidimen.html

[Roybot06]

I tried that, but I need them to randomize in sync.

 

And I can't figure a way to tell the array to place a specific method or tag somewhere...do arrays only take a character string or can I tell it to take the "<a href =\"#"> and move it with the pictures?

[dbo]

I don't understand your response but a multidimensional array will work.

 

$arr = Array();

$arr[] = Array("www.thisisaurl.com", "thisisanimage.jpg");

 

So then you randomly select an index between 0 and the maximum number of array elements - 1. At this index you do this:

 

$url = $arr[$randomlyselectedindexhere][0];

$img = $arr[$randomlyselectedindexhere][1];

 

You've now got your add and it's associated link.

[keeB]

<?php

$total = count($array_with_ads);

$randomAd = rand(0, $total)

print $array_with_ad[$randomAd];
?>

 

 

This what you want?

[dbo]

I don't think it is. Sounded like he needed an ad (image) and a url. Your code will just give one. I'm pretty sure that's what he/she had to begin with.

[LiamProductions]

<?php

$rand = rand(1,4);

case $rand:
     case 1:
     echo "Imageurl.gif";
     break;
     case 2:
     echo "imageurl2.gif2;
     break;
    default:
    echo "No image was produced";

 

not sure, if that case works but i'm sure the rand() function is giving you idea how you could do it

[Roybot06]

Thank you guys, I have come up with a solution for this. It took a few days, but I couldn't thank you all enough.

 

Now to my next problem!