reecieboy Posted April 9, 2006 Share Posted April 9, 2006 hey can someone please help me debug the following: [a href=\"http://pastebin.com/649448\" target=\"_blank\"]http://pastebin.com/649448[/a]anyhelp is highly appreciated Quote Link to comment Share on other sites More sharing options...
theone Posted April 9, 2006 Share Posted April 9, 2006 well lets start with basic html. tahoma is not a font family its merely a font face. a family consists of more than one.but you need to be more specific as to what is not working or what errors its spitting out. Quote Link to comment Share on other sites More sharing options...
reecieboy Posted April 9, 2006 Author Share Posted April 9, 2006 [!--quoteo(post=362974:date=Apr 9 2006, 08:26 AM:name=theone)--][div class=\'quotetop\']QUOTE(theone @ Apr 9 2006, 08:26 AM) [snapback]362974[/snapback][/div][div class=\'quotemain\'][!--quotec--]well lets start with basic html. tahoma is not a font family its merely a font face. a family consists of more than one.but you need to be more specific as to what is not working or what errors its spitting out.[/quote]ok fair enough lol. umm [a href=\"http://203.87.72.141/login.php\" target=\"_blank\"]http://203.87.72.141/login.php[/a] mysql fetch array is not a valid resource.. and cheers for this :D Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 9, 2006 Share Posted April 9, 2006 You do realize that you posted your root password for the world to see when you posted your code?Ken Quote Link to comment Share on other sites More sharing options...
reecieboy Posted April 9, 2006 Author Share Posted April 9, 2006 thanks for pointing that out, fixed Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 9, 2006 Share Posted April 9, 2006 Use multiple lines for you query so debugging is easier:[code]<?php$q = "SELECT * FROM users WHERE userid='". $_POST['username']. "' AND passid='".$_POST['password'] . "'";$rs = mysql_query($q) or die('Problem with query: ' . $q . '<br />' . mysql_error());$qquery = mysql_fetch_array($rs);?>[/code]Ken Quote Link to comment Share on other sites More sharing options...
reecieboy Posted April 9, 2006 Author Share Posted April 9, 2006 thanks hold up ill try that Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 9, 2006 Share Posted April 9, 2006 BTW, here's your code modified to use CSS instead of embedded styles:[code]<html><head><title>PWN|CLAN - Login</title><style>body { background-color: Black; color: White; font-family: Tahoma, sans-serif; font-size: 100%;}#userpass { width: 60px; border-color:#777777; background-color: #FFFFFF; color: #000000;}#subm { border-color: #777777; background-color: #FFFFFF; color: #000000;}</style></head><body><?phpif (!isset($_POST['submit']) || (isset($_POST['submit']) && $_POST['username'] == '') || (isset($_POST['submit']) && $_POST['password'] == '')) { echo "<form name='zlogin' method='POST' action='" . $_SERVER['PHP_SELF'] . "'>"; echo "Username: <input type='text' name='username' id='userpass'><br>"; echo "Password: <input type='password' name='password' id='userpass'><br>"; echo "<input type='submit' name='submit' value='Login' id='subm'> <input type='reset' name='reset' value='Reset' id='subm'>"; echo "</form>"; }else { mysql_connect("localhost", "***", "***") OR die('password'); mysql_select_db("main") OR die('Connecting'); $q = "SELECT * FROM users WHERE userid='". $_POST['username']. "' AND passid='".$_POST['password'] . "'"; $rs = mysql_query($q) or die('Problem with query: ' . $q . '<br />' . mysql_error()); $qquery = mysql_fetch_array($rs); if ($qquery['username'] == $_POST['username'] && $qquery['password'] == $_POST['password']) { session_name('login'); session_start(); $_SESSION['username'] = $_POST['username']; $_SESSION['password'] = $_POST['password']; echo $fontfamily."Successfully logged in as: ".$_POST['username']."<br><a href='index.php?page=your_account'>Click here to continue...</a></font>"; }else { echo $fontfamily."Login failed,<br><a href='index.php?page=login'>Click here to try again...</a></font>"; } }?></body></html>[/code]Ken Quote Link to comment Share on other sites More sharing options...
reecieboy Posted April 9, 2006 Author Share Posted April 9, 2006 thank you, it now works :D Quote Link to comment Share on other sites More sharing options...
SomeGuy1337 Posted April 9, 2006 Share Posted April 9, 2006 be sure to use the CSS very important to move away from that horrible html sytles, u will learn that the hard way if you dont learn it now. Quote Link to comment Share on other sites More sharing options...
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