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AHH! I am riping my hair out!

 

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Edit my Garage</title>
</head>

<body>
<form action="insert_garage.php" method="POST">
   	<p>What do you call your garage? 
   	    <input type="text" name="Name" />
        <br/>
        What size is your garage? (1 car, 2 car, etc) 
        <input name="Size" type="text" />
        <br/>
        Location? (Oshkosh, WI) 
        <input name="Location" type="text" />
        <br/>
        Info:
        <br/>
      <textarea name="" cols="50" rows="10">Enter a breif discription here!</textarea>
	<br/>
        <input type="submit" />
</form>
</body>
</html>

 

And Insert_garage.php looks like...

 

<?php
$con = mysql_connect("localhost","*****","******");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
mysql_select_db("****_****", $con);

$sql="INSERT INTO Garage (Name, Size, Location, Info)
VALUES
('$_POST[Name]','$_POST[size]','$_POST[Location]','$_POST[info])";if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }
echo "You Garage Page has been updated";mysql_close($con)
?>

 

I get an error that line three of Insert_garage.php isnt right? Whats wrong? Thanks alot

Link to comment
https://forums.phpfreaks.com/topic/69417-what-is-wrong-here/
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whats the error message you get?

 

also you could just do:

 

$con = mysql_connect("localhost","*****","******") or die('Could not connect: ' . mysql_error());

 

and leave out the whole if statement

 

 

OH, and you're missing a ; at the very end - after mysql_close($con);

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https://forums.phpfreaks.com/topic/69417-what-is-wrong-here/#findComment-348773
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