dave456 Posted September 15, 2007 Share Posted September 15, 2007 AHH! I am riping my hair out! <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Edit my Garage</title> </head> <body> <form action="insert_garage.php" method="POST"> <p>What do you call your garage? <input type="text" name="Name" /> <br/> What size is your garage? (1 car, 2 car, etc) <input name="Size" type="text" /> <br/> Location? (Oshkosh, WI) <input name="Location" type="text" /> <br/> Info: <br/> <textarea name="" cols="50" rows="10">Enter a breif discription here!</textarea> <br/> <input type="submit" /> </form> </body> </html> And Insert_garage.php looks like... <?php $con = mysql_connect("localhost","*****","******"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("****_****", $con); $sql="INSERT INTO Garage (Name, Size, Location, Info) VALUES ('$_POST[Name]','$_POST[size]','$_POST[Location]','$_POST[info])";if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "You Garage Page has been updated";mysql_close($con) ?> I get an error that line three of Insert_garage.php isnt right? Whats wrong? Thanks alot Quote Link to comment Share on other sites More sharing options...
micah1701 Posted September 15, 2007 Share Posted September 15, 2007 whats the error message you get? also you could just do: $con = mysql_connect("localhost","*****","******") or die('Could not connect: ' . mysql_error()); and leave out the whole if statement OH, and you're missing a ; at the very end - after mysql_close($con); Quote Link to comment Share on other sites More sharing options...
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