choose randomly

[11Tami]

Hello, how would I get this to choose a line of text randomly instead of in order so it doesn't pick the same one twice in a row? Please let me know, thanks very much.

 

<?php 
$maximum=3; 
$a = (isset($_COOKIE['e']) && intval($_COOKIE['e']) < $maximum)? intval($_COOKIE['e'])+1 : 1; 
setcookie("e", $a, time()+60*60*24*180); 
$text[1] = "test1"; 
$text[2] = "test2"; 
$text[3] = "test3";
php echo "$text[$a]";
?> 

[darkfreaks]

<?php echo rand($text[$a]);  ?>

[11Tami]

Thank you, it doesn't like those there, think its looking for numbers.

[11Tami]

Maybe there's a way to get it to output a number from the array first like 1, 2, or 3 and then put that into the random function? Anyone know how to get it to output an array number? Or maybe there is an easier way.

 

I was missing the whole code, here's all of it.

 

<?php 
$maximum=3; 
$a = (isset($_COOKIE['e']) && intval($_COOKIE['e']) < $maximum)? intval($_COOKIE['e'])+1 : 1; 
setcookie("e", $a, time()+60*60*24*180); 
$text = Array();
$text[1] = "test1"; 
$text[2] = "test2"; 
$text[3] = "test3";
php echo "$text[$a]";
?> 

[corbin]

Well you could generate a random number between 0 and the number of keys -1.  Example:

 

$array = array('Corbin', 'Is', 'Awesome');
$random = $array[rand(0, count($array)) - 1]; //the count isn't necesary if you know the number of keys....

[11Tami]

Thanks, I looked up keys but don't know what you mean by number of keys. I need to keep the numbers in the array because I'll be rotating other numbers as well. Maybe it can be done without the cookies as well, since its random.

[d22552000]

uh.. by looking at your php, shouldnt this be under php math?  "intval"

[11Tami]

I've got this:

 

<?php
$text = Array(); 
$text[1] = "test1"; 
$text[2] = "test2"; 
$text[3] = "test3";
$get = $text[rand(1, 3)];
echo $get;
?> 

 

It's working, now I just need to keep the same one from occurring twice in a row. Not sure how.

[d22552000]

should you do rand (1,3); and then say if it equals 1 then text[1] ?? idk what you want lol/