anocweb Posted September 21, 2007 Share Posted September 21, 2007 i have a website that inserts an item into a database and then uploads the images for a catalog up till recently it worked fine then the owner started having issues. the upload would work but the database wouldn't have the entry in it. but it worked for me. then just shortly after it stopped working for me as well. i dont get any errors from mysql, or php im running apache 2.0.52, php 4.3.9-3.22.5, and mysql 4.1.20-2.RHEL4.1. the mysql variables are in this file: mysql.inc.php <?PHP $servername="localhost"; # enter location of database server $username="marty"; # enter your username for the database $password="*******"; # enter you password for the database $port="3306"; # default is always 3306 $database="content"; # database to connect to ?> the rest of the code is here: card_upload.php <?PHP include('header.inc.php'); include('../mysql.inc.php'); ?> <?php # connect to database $connect = $servername . ":" . $port; $sql = mysql_connect($connect,$username,$password); # check if connection succeeded if (!$sql) {die('Could not connect: ' . mysql_error());} # selects the database mysql_select_db($database, $sql); if ($_POST['step'] == "4") { move_uploaded_file ($_FILES['uploadFile'] ['tmp_name'], "/var/www/vhosts/tradeart.no-ip.org/httpdocs/cards/" . $_POST['style'] . ".a.jpg"); chmod("/var/www/vhosts/tradeart.no-ip.org/httpdocs/cards/" . $_POST['style'] . ".a.jpg", 0777); echo 'DONE UPLOADING ' . $_POST['style'] . '!'; } elseif ($_POST['step'] == "3") { move_uploaded_file ($_FILES['uploadFile'] ['tmp_name'], "/var/www/vhosts/tradeart.no-ip.org/httpdocs/cards/" . $_POST['style'] . ".i.jpg"); chmod("/var/www/vhosts/tradeart.no-ip.org/httpdocs/cards/" . $_POST['style'] . ".i.jpg", 0777); echo '<form method="post" enctype="multipart/form-data" url="card_upload.php"><table style="text-align: left; width: 80%;" border="0" cellpadding="2" cellspacing="2"> <tbody><input type="hidden" name="step" value="4"><input type="hidden" name="style" value="' . $_POST['style'] . '"> <tr> <td>Inside Image:</td> <td><input name="uploadFile" type="file"></td> </tr> <tr> <td></td> <td><input value="step 4" type="submit"></form></td> </tr> </tbody> </table>'; } elseif ($_POST['step'] == "2") { $inset = 'cards/' . $_POST['style'] . '.a.jpg'; $location = 'cards/' . $_POST['style'] . '.i.jpg'; $check = mysql_query("INSERT INTO product (style, description, category, location, inset, wide) VALUES ('" . $_POST['style'] . "', '" . $_POST['desc'] . "', '" . $_POST['cat'] . "', '$location', '$inset', '" . $_POST['wide'] . "')")or die(mysql_error()); if ($check == "false") { echo "ERROR PLEASE GO BACK!<br />"; } echo '<form method="post" enctype="multipart/form-data" url="card_upload.php"><table style="text-align: left; width: 80%;" border="0" cellpadding="2" cellspacing="2"> <tbody><input type="hidden" name="step" value="3"><input type="hidden" name="style" value="' . $_POST['style'] . '"> <tr> <td>Outside Image:</td> <td><input name="uploadFile" type="file"></td> </tr> <tr> <td></td> <td><input value="step 3" type="submit"></form></td> </tr> </tbody> </table>'; } else { echo '<table style="text-align: left; width: 80%;" border="0" cellpadding="2" cellspacing="2"> <tbody> <tr> <td style="text-align: right;">Style</td> <td><form method="post" url="card_upload.php"><input type="hidden" name="step" value="2"><input name="style"></td> </tr> <tr> <td style="text-align: right;">Category</td> <td> <select size="1" name="cat">'; $result = mysql_query("SELECT * FROM category"); while($row = mysql_fetch_array($result)) { echo '<option>' . $row['cat'] . '</option>'; } echo '</select> </td> </tr> <tr> <td></td> <td>Horizontal<input checked="checked" name="wide" value="1" type="radio"> Vertical <input name="wide" value="0" type="radio"> </td> </tr> <tr> <td style="text-align: right;">Description</td> <td><textarea cols="35" rows="3" name="desc"></textarea></td> </tr> <tr> <td></td> <td><input value="Step 2" type="submit"></form></td> </tr> </tbody> </table>'; } mysql_close($sql); ?> <?PHP include('footer.inc.php'); ?> Quote Link to comment Share on other sites More sharing options...
fenway Posted September 21, 2007 Share Posted September 21, 2007 We don't need all of that code... echo the insert query to the screen. Quote Link to comment Share on other sites More sharing options...
anocweb Posted September 21, 2007 Author Share Posted September 21, 2007 i apologize. query mysql_query("INSERT INTO product (style, description, category, location, inset, wide) VALUES ('" . $_POST['style'] . "', '" . $_POST['desc'] . "', '" . $_POST['cat'] . "', '$location', '$inset', '" . $_POST['wide'] . "')")or die(mysql_error()); the structure is as follows as well CREATE TABLE `product` ( `key` int(255) unsigned NOT NULL auto_increment, `style` varchar( NOT NULL default '', `description` text, `category` varchar(30) NOT NULL default '', `location` varchar(45) NOT NULL default '', `inset` varchar(45) NOT NULL default '', `wide` char(1) default NULL, PRIMARY KEY (`key`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 Quote Link to comment Share on other sites More sharing options...
anocweb Posted September 21, 2007 Author Share Posted September 21, 2007 --bump ideas anybody? Quote Link to comment Share on other sites More sharing options...
fenway Posted September 24, 2007 Share Posted September 24, 2007 That's not echoing the query to the screen... that's copying and pasting php code, which I've already seen. It doesn't help me. Store that query in a variable, and echo that variable to the screen, then post it here -- just the sql, not the php. Quote Link to comment Share on other sites More sharing options...
anocweb Posted September 24, 2007 Author Share Posted September 24, 2007 it echos "false" Quote Link to comment Share on other sites More sharing options...
fenway Posted September 24, 2007 Share Posted September 24, 2007 it echos "false" No it doesn't. Not the return value of the mysql_query() call... the actual query itself. Quote Link to comment Share on other sites More sharing options...
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