Aljade Posted April 11, 2006 Share Posted April 11, 2006 [code]function showHideOtherTax(job_id) { var tax_field = 'job'+job_id+'other_tax'; if(document.proposal.tax_field.selectedIndex == 2) { document.getElementById('job'+job_id+'other_tax_div').style.display = ""; }}[/code]The if statement doesn't work in this function. If type in say job1othertax instead of using tax_field it works, but I need it to work according to what job_id is. How can I fix this?Thanks! Quote Link to comment https://forums.phpfreaks.com/topic/7081-if-statement-help/ Share on other sites More sharing options...
GBS Posted April 19, 2006 Share Posted April 19, 2006 Hi there,I'm not sure,, but,, maybe you have a typo mistake there, between 'other_tax' / 'other_tax_id',... [!--quoteo--][div class=\'quotetop\']QUOTE[/div][div class=\'quotemain\'][!--quotec--]function showHideOtherTax(job_id) { var tax_field = 'job'+job_id+'other_tax'; if(document.proposal.tax_field.selectedIndex == 2) { document.getElementById('job'+job_id+'[b]other_tax[/b]').style.display = ""; }}[/quote]Anyway,, you could maybe try the eval() javascript function:[code] if(document.proposal.tax_field.selectedIndex == 2) { eval("document.getElementById('job'+job_id+'other_tax').style.display = ''; "); }[/code]Good luck,l8tr,, Quote Link to comment https://forums.phpfreaks.com/topic/7081-if-statement-help/#findComment-28794 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.