[SOLVED] Fairly simple syntax question

[peps666]

First post on this forum!

 

I'm currently developping a web program at my job. In some scripts, i have fairly long list of conditions before showing something. Here's a short example:

 

if(($a==2 OR $a==4 OR $a==31))

{

echo "this";

}

 

I'm trying to save some space in the code to make it more readable. I tried to write it like this but it's not working...

 

if(($a==(2 OR 4 OR 31))

{

echo "$a";

}

 

I tried this also...

 

if(($a==(2 || 4 || 31))

{

echo "$a";

}

 

Is there a way to write correctly a statement in the way it is above? Thanks!

 

[cooldude832]

first off The word OR is a mysql operator not php secondly you can say

if($a is this or that or that) you must say

if($s is this or $a is that or $a is that) such as

if($a = 5 || $a = 6 || $a =

 

that holds true if $a is 5 6 or 8 also you can't test if 5<$a<8 you must say if($a>5 && $a <

 

to make stuff clearer try using a function based test, or try this

 

<?php 
$tester = array(5,6,
$a = 2;
if(in_array($a,$tester)){
//it matched
}
?>

make sense?

[peps666]

Yep excellent.

 

I thought there was some way to simply write if $a==(2 || 4 || It seems not. That's alright.

 

The idea of the array in the function is good.

 

Thank you. Case solved.

[trq]

first off The word OR is a mysql operator not php

 

Not true.

 

if(($a==2 OR $a==4 OR $a==31))
{
echo "this";
}

 

is perfectly valid php.