flOid Posted April 11, 2006 Share Posted April 11, 2006 I have written a small script which outputs the total number of seconds of a MP3 playlist stored in a database. But I would like to output total hours and minutes of the playlist like "the playlist has a running time of xx hours and xx minutes".I'm a PHP newbie and bad in maths, so could anyone provide me the needed algo? Quote Link to comment Share on other sites More sharing options...
Twentyoneth Posted April 11, 2006 Share Posted April 11, 2006 $totaltime = 360 (seconds)$hours = (($totaltime / 60) / 60);echo $hours;That should give you a decimal point number, like 0.something hours....that would be my best try :S Quote Link to comment Share on other sites More sharing options...
flOid Posted April 11, 2006 Author Share Posted April 11, 2006 [!--quoteo(post=363795:date=Apr 11 2006, 04:05 PM:name=Twentyoneth)--][div class=\'quotetop\']QUOTE(Twentyoneth @ Apr 11 2006, 04:05 PM) [snapback]363795[/snapback][/div][div class=\'quotemain\'][!--quotec--]$totaltime = 360 (seconds)$hours = (($totaltime / 60) / 60);echo $hours;That should give you a decimal point number, like 0.something hours....that would be my best try :S[/quote]thanx, but that was not what I was looking for, I actually could have done that by myself. What I was looking for was not a decimal number but seperated values for total hours and minutes. Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 11, 2006 Share Posted April 11, 2006 Here is function I wrote a while back... It should help you with your problem.[code]<?phpfunction time_diff($in_date){ $minute = 60; $hour = 60 * 60; $day = $hour * 24; $now = time(); $start = strtotime($in_date); $seconds_left = $now - $start; $days_left = floor($seconds_left / $day); $hours_left = floor(($seconds_left % $day)/$hour); $minutes_left = floor((($seconds_left % $day) % $hour) / $minute); $seconds = $seconds_left - ($days_left * $day) - ($hours_left * $hour) - ($minutes_left * $minute); return (array($days_left,$hours_left,$minutes_left,$seconds));}echo '<pre>' . print_r(time_diff('2006-01-01'),true) . '</pre>';?>[/code]Ken Quote Link to comment Share on other sites More sharing options...
flOid Posted April 12, 2006 Author Share Posted April 12, 2006 [!--quoteo(post=363812:date=Apr 11 2006, 04:49 PM:name=kenrbnsn)--][div class=\'quotetop\']QUOTE(kenrbnsn @ Apr 11 2006, 04:49 PM) [snapback]363812[/snapback][/div][div class=\'quotemain\'][!--quotec--]Here is function I wrote a while back... It should help you with your problem.[code]<?phpfunction time_diff($in_date){ $minute = 60; $hour = 60 * 60; $day = $hour * 24; $now = time(); $start = strtotime($in_date); $seconds_left = $now - $start; $days_left = floor($seconds_left / $day); $hours_left = floor(($seconds_left % $day)/$hour); $minutes_left = floor((($seconds_left % $day) % $hour) / $minute); $seconds = $seconds_left - ($days_left * $day) - ($hours_left * $hour) - ($minutes_left * $minute); return (array($days_left,$hours_left,$minutes_left,$seconds));}echo '<pre>' . print_r(time_diff('2006-01-01'),true) . '</pre>';?>[/code]Ken[/quote]Indeed that was very helpful! My script is working now, thanx a lot! :) Quote Link to comment Share on other sites More sharing options...
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