[SOLVED] Question

[shage]

echo '<LINK REL = "STYLESHEET" TYPE "text/css" HREF ="$myRandomText.css">';

 

what am i doing wrong there, Im trying to echo the $myrandomtext i know that dont look right but hey im new please and thank you

[micah1701]

when including a PHP variable inside an outputted HTML string, you either need to encase the whole thing in double quotes, or break out of the string.

 

either of these will work:

<?php

echo "<LINK REL = \"STYLESHEET\" TYPE \"text/css\" HREF =\"$myRandomText.css\">";

// or

echo '<LINK REL = "STYLESHEET" TYPE "text/css" HREF ="'.$myRandomText.css.'">';

?>

 

 

EDIT -- to better explain:

<?php

$var = "world";

echo "hello $var"; //outputs: hello world
echo 'hello $var';  //outputs: hello $var
echo 'hello '.$var; //outputs: hello world

?>