amosse Posted October 4, 2007 Share Posted October 4, 2007 Hello to everybody, I am a beginner in php/mysql and have to build e query with calculated filed, this is my problem: I have this somple query, select id,date_format(fin_record_date,'%d-%m-%y') as fin_record_date_it,fin_record_debit,fin_record_credit,(fin_record_debit-fin_record_credit) as fin_record_bal1 from fin_records; Subsequently while fetching query I use php in order to calculate progressive balance in this way, $fin_record_bal2 +=$row2[fin_record_bal1]; My question is: do you know one system in order to get same result in query statement without using PHP? Thanks for your attention. Amos Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/ Share on other sites More sharing options...
kirk112 Posted October 4, 2007 Share Posted October 4, 2007 Take a look at WITH ROLLUP function this might be what you are looking for http://dev.mysql.com/doc/refman/4.1/en/group-by-modifiers.html this will give you an extra row with all the values in the coloum added up. If you do not need to loop through each record after the query has run you could use SUM((fin_record_debit-fin_record_credit)) as fin_record_bal1 Hope this points you in the right direction Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-361531 Share on other sites More sharing options...
amosse Posted October 4, 2007 Author Share Posted October 4, 2007 Thank you for your reply. I checked but my problem is that I need to display all records, I tried something like this: select id,date_format(fin_record_date,'%d-%m-%y') as fin_record_date_it,fin_record_debit,fin_record_credit,(sum(fin_record_debit-fin_record_credit)) as fin_record_bal1 from fin_records group by fin_record_date with rollup but is not working because I need to have o total (an addition row) for each row. I would like to ask you another question: How can I import data in MySQL from an Open Office (DB) Table? Many thanks. Amos Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-361656 Share on other sites More sharing options...
fenway Posted October 6, 2007 Share Posted October 6, 2007 You can use user variables for "row-based" counts/sums. As for the import, I assume it's CSV-able, and mysql actually has such a table type (or LOAD DATA INFILE from any tab-separated file). Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-363252 Share on other sites More sharing options...
amosse Posted October 6, 2007 Author Share Posted October 6, 2007 Thak you very much for your reply Mr Fenway, I would like to ask you where can I find information or samples about user variables for "row-based" counts/sums method? I checked on Mysql web site but I didn't find the right argument. Many thanks. Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-363284 Share on other sites More sharing options...
fenway Posted October 7, 2007 Share Posted October 7, 2007 Take a look here. Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-364026 Share on other sites More sharing options...
amosse Posted October 8, 2007 Author Share Posted October 8, 2007 Thank you for your reply. I red documentation as per your reply, I tried to do this select id,fin_record_debit,fin_record_credit,@bal1:=fin_record_debit-fin_record_credit as bal1,@bal2:=@bal2+(fin_record_debit-fin_record_credit) as balance from fin_records but I get "NULL for balance column" select id,fin_record_debit,fin_record_credit,@bal1:=fin_record_debit-fin_record_credit as bal1,@bal2:=@bal2+@bal1 into @balance from fin_records but I get "The used SELECT statements have a different number of columns" I don't, can you give some little help? Many thanks. Amos Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-364901 Share on other sites More sharing options...
amosse Posted October 8, 2007 Author Share Posted October 8, 2007 Sorry I have 5.0.22 essential MySQL version. Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-364907 Share on other sites More sharing options...
fenway Posted October 9, 2007 Share Posted October 9, 2007 You haven't set the user variable first. Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-365101 Share on other sites More sharing options...
amosse Posted October 9, 2007 Author Share Posted October 9, 2007 Do you mean like this: set @bal1=fin_record_debit-fin_record_credit,@bal2=0; select id,fin_record_debit,fin_record_credit,@bal2:=(@bal1:=+@bal2) from fin_records; or like this: set @bal1=fin_record_debit-fin_record_credit,@bal2=@bal1; select id,fin_record_debit,fin_record_credit,@bal2:=(@bal1+@bal2) from fin_records; it is steel NULL.. I don't know if you can give some more advice? Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-365254 Share on other sites More sharing options...
amosse Posted October 9, 2007 Author Share Posted October 9, 2007 I tried (from Follow up on rolling sum - self join vs user variables) as well: select id,fin_record_debit,fin_record_credit,(fin_record_debit-fin_record_credit) as bal1, @runtot:=@runtot+bal1 as runtot from (select id,fin_record_debit,fin_record_credit, (fin_record_debit-fin_record_credit) as bal1 from fin_records) as t still NULL for runtot Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-365285 Share on other sites More sharing options...
fenway Posted October 9, 2007 Share Posted October 9, 2007 You can't initialize it to a variable first! Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-365297 Share on other sites More sharing options...
amosse Posted October 9, 2007 Author Share Posted October 9, 2007 I don't understand excuse me I am a beginner, What is wrong in my previous example, could you be more explicit? Could you help me a bit more? Many thanks. Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-365733 Share on other sites More sharing options...
fenway Posted October 10, 2007 Share Posted October 10, 2007 Try SET @runtot:=0, then select it on the next line. Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-366215 Share on other sites More sharing options...
amosse Posted October 10, 2007 Author Share Posted October 10, 2007 Thank you for your reply. I tried to do this: SET @runtot:=0; select id,@runtot from fin_records; Still @runtot = NULL I don't understand manual say "If you refer to a variable that has nor been inizialized, it has a value of NULL and a type of string" now to inizialize a variable is SET statement? I tried even SET @runtot:=1; select id,@runtot from fin_records; Still @runtot = NULL I don't understand, please tell me if the concept is right? If it is, running sum will never work or not? Thanks again Amos ps: I have 5.0.22 Windows Essentials (x86) Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-366444 Share on other sites More sharing options...
fenway Posted October 11, 2007 Share Posted October 11, 2007 What do you get from this: SET @t1=0, @t2=0, @t3=0; SELECT @t1:=(@t2:=1)+@t3:=4,@t1,@t2,@t3; Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-367289 Share on other sites More sharing options...
amosse Posted October 11, 2007 Author Share Posted October 11, 2007 I get: @t1:=(@t2:=1)+@t3:=4 Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-367456 Share on other sites More sharing options...
amosse Posted October 11, 2007 Author Share Posted October 11, 2007 Excuse me,previous message is incomplete: I get 5,5,1,4 like manual : http://dev.mysql.com/doc/refman/5.1/en/user-variables.html it seems to be ok...for mysql 5.1.. may be it needs to up date release from 5.0 to 5.1? Thank you for your attention. Amos Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-367461 Share on other sites More sharing options...
fenway Posted October 12, 2007 Share Posted October 12, 2007 User variables have been around since 3.23... Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-367816 Share on other sites More sharing options...
amosse Posted October 12, 2007 Author Share Posted October 12, 2007 Do you think can I do something in order to get result? Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-368009 Share on other sites More sharing options...
fenway Posted October 12, 2007 Share Posted October 12, 2007 Just try a simple row counter first. Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-368019 Share on other sites More sharing options...
amosse Posted October 13, 2007 Author Share Posted October 13, 2007 Sorry but really I don't understand... You refered to manual (http://dev.mysql.com/doc/refman/5.1/en/user-variables.html) with the statement set @t1=0,@t2=0,@t3=0; SELECT @t1:=(@t2:=1)+@t3:=4,@t1,@t2,@t3 that is working giving me the result: 5,5,1,4 In the same http page mentionned above you can find a post (the 1 st-one) of Joey Bartlett where is reporting the following statement: set @pos=0; select @pos:=@pos+1,name from players order by score desc; Now if I take same sample above and I adapt to my table in this way: set @pos=0; select @pos:=@pos+1,id,fin_record_desc from fin_records order by id; I get column @pos:=@pos+1 NULL Please someone can tell me why the above statement is not working.....? If the above sample is not working I assume that running sum will never work.... I would apreciate someone who can demostrate the contrary. here the table as per the sample above: DROP TABLE IF EXISTS `fin_records`; CREATE TABLE `fin_records` ( `id` int(10) unsigned NOT NULL auto_increment, `fin_record_date` date NOT NULL default '0000-00-00', `id_bank_account` int(10) unsigned NOT NULL default '0', `id_fin_account` int(10) unsigned NOT NULL default '0', `fin_record_desc` varchar(45) NOT NULL default '', `fin_record_debit` double(9,2) unsigned NOT NULL default '0.00', `fin_record_credit` double(9,2) unsigned NOT NULL default '0.00', `fin_record_rec` tinyint(4) unsigned NOT NULL default '0', `id_production_unit` int(10) unsigned NOT NULL default '0', PRIMARY KEY (`id`), UNIQUE KEY `date_unit_account_fincode` (`fin_record_date`,`id_production_unit`,`id_fin_account`,`id_bank_account`,`fin_record_rec`,`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 COMMENT='cash & bank records; InnoDB free: 4096 kB; (`id_bank_account'; Ciao Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-368737 Share on other sites More sharing options...
amosse Posted October 13, 2007 Author Share Posted October 13, 2007 Ok I got running sum: here is the statement select x1.id,x1.fin_record_date,x1.added,sum(x2.added) as runningtotal from (select id,fin_record_date,count(*) as added from fin_records group by fin_record_date) as x1 inner join (select id,fin_record_date,count(*) as added from fin_records group by fin_record_date) as x2 on x1.id >= x2.id group by x1.fin_record_date; Now I have to adapt it to my case. Quote Link to comment https://forums.phpfreaks.com/topic/71786-help-building-an-alias-field/#findComment-368770 Share on other sites More sharing options...
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