syntax

[angelsRock]

why my $subid shows nothing?? thanks

 

echo '<form action="post-premiumreview.php?id="$subid method=POST>';

[ShoeLace1291]

try

 

echo "<form action='post-premiumreview.php?id=$subid' method=POST>";

[darkfreaks]

<?php echo "<form action=post-premiumreview.php?id=$subid method=POST>";?>

 

this should work purfect

[GingerRobot]

Strings enclosed in single quotes are taken to be literal - that is, any variables inside them are not evaluated. For example:

 

<?php
$foo = 'bar';
echo 'The string is: $foo';
?>

Produces the exact text:  The string is: $foo

 

If you enclose the string in double quotes, however, variables are evaluated. So:

<?php
$foo ='bar';
echo "The string is: $foo";
?>

Produces: The string is bar

 

So, if you want to echo variables within your string, you must either use double quotes or concatenation:

 

<?php
$var = 'some variable';
//either
echo "Some other text $var a bit more text";
// or
echo 'Some other text '.$var.' a bit more text';
?>

[darkfreaks]

ah sorry it was bad  coding thanks ginger worked on my coding though it was javascript but still worked i guess she could do something like

 

 

<?php echo '<form action='post-premiumreview.php?id=.$subid.' method=POST>';?>

[GingerRobot]

ah sorry it was bad  coding thanks ginger worked on my coding though it was javascript but still worked i guess she could do something like

 

 

<?php echo '<form action='post-premiumreview.php?id=.$subid.' method=POST>';?>

 

That wouldn't work. You'd need to do:

<?php echo '<form action="post-premiumreview.php?id='.$subid.'" method="POST">';?>