# Multiples of Integers

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### #1 Jarin

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Posted 14 April 2006 - 04:29 AM

Well, considering I'm not very math savvy, I need a bit of help. I'm trying to determine whether one integer is evenly divisible into another integer, IE is 1033343 a multiple of 3, is 105 a multiple of 5, etc. How would one go about determining this in a memory-conservative manner?

### #2 KrisNz

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Posted 14 April 2006 - 04:38 AM

[!--quoteo(post=364686:date=Apr 14 2006, 02:29 PM:name=Jarin)--][div class=\'quotetop\']QUOTE(Jarin @ Apr 14 2006, 02:29 PM) [/div][div class=\'quotemain\'][!--quotec--]
Well, considering I'm not very math savvy, I need a bit of help. I'm trying to determine whether one integer is evenly divisible into another integer, IE is 1033343 a multiple of 3, is 105 a multiple of 5, etc. How would one go about determining this in a memory-conservative manner?

[/quote]
use the '%' operator which gives you the remainder of a division. e.g \$i = 5 % 5; #\$i=0;

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Posted 14 April 2006 - 04:39 AM

You could probably just use the Modulus operator. This basically divides 2 numbers and tells you what the remainder is. So you could test and see if it's equal to 0, and if so, then you know that one number is a multiple of another. Here's an example using the numbers from your example:

```\$a = 1033343;
\$b = 3;
\$result = \$a % \$b;
if (\$result == 0)
echo 'the two numbers are evenly divisible';
else
echo 'the two numbers are not evenly divisible';
```

### #4 Jarin

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Posted 14 April 2006 - 03:17 PM

Never knew that operator existed. Thanks a lot guys, much appreciated!

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