[SOLVED] embedding variable into function name not working???

[darksniperx]

<?php
$name = 'Entry';
include 'test.php';-> I would like to change it to-> include '$name.php';
show.$name.();
?>

 

I would like to automate my php code and reduce at the same time. I pass one variable that contains text value, so that php would use that variable name inside include and function name. It should be possible?

[trq]

You can easily use a variable to include a file....

 

<?php

  $name = 'Entry';
  include $name . '.php';

?>

 

But dynamically calling a function is a little more difficult....

 

<?php

  $name = 'Entry';
  include $name . '.php';
  call_user_func('show' . $name);

?>

[darksniperx]

nice!!!!, I have one ,more question, it is possible to pass a parameter with call_user_func('show' . $name); to be something like this showEntry($value); or I have to hard code to pass a parameter?

[derwert]

 

http://www.php.net/manual/en/function.call-user-func.php

 

<?php

  $name = 'Entry';
  include $name . '.php';
  call_user_func('show' . $name, $value);

?>

[darksniperx]

I did check php.net, I guess I have missread. Anyways, thx, everething works now.

[Barand]

<?php
function funcA ()
{
    echo "<p>A called</p>";
    
}

function funcB ()
{
    echo "<p>B called</p>";
    
}

if (isset($_GET['func']))
{
    $x = 'func'.$_GET['func'];
    
    $x();                               // call chosen dynamic function
}
?>
<form>
Call <input type="radio" name="func" value="A"> A <input type="radio" name="func" value="B"> B
<input type="submit" name="sub" value="Call">
</form>

[darksniperx]

interesting, havent thought about it this way, I guess php is very robust. Just hope it will work with php 4, I'll work with both of them, each one has a very unique use for me.

[Barand]

Works in 4.3.9 and 5.1.2

[darksniperx]

I should have 4.3.9 or something higher, I worked when I tested it out.