Getting "Days Remaining"

[habanero25]

Hello,

 

I have written a program that gets the date, and compares it with a "Sale Date". If the current date is before the sale date (November 22nd, 2007), it will print "Sale is on!". If it is after, it will print "Sale is over...".

 

	
                $freestuffdate = "22-11-07";	
	$today = date("d-m-y");
	if ($freestuffdate >= $today){
		echo "Sale is on!<br />";
	}
	elseif ($freestuffdate<$today){
		echo "Sale is over...<br />";
	}

 

I am wondering if there is any way to make a code that prints out how many days are left until the end of the sale. How can I tell PHP to subtract $today from $freestuffdate, so that it tells me how many days are left from the current date and the sale date?

 

Thank you in advance,

Habanero

[Barand]

<?php
$freestuffdate = "22-11-07";
list ($d,$m,$y) = explode('-', $freestuffdate);

$freestufftime = mktime(0,0,0,$m,$d,$y);
$daystogo = floor(($freestufftime - time()) / 86400);

echo $daystogo;
?>

[corillo181]

this is something i did very quick so try it out.

maybe Barand ones is better which ever one you feel more comfortable.

 

this a class

 

<?php

class sales{
var $today;
var $saledate;

function sales($d,$m,$y){
	$this->saledate = mktime(0,0,0,$m,$d,$y);
	$this->today = date("d-m-y");

}

function daysLeft(){
	$daysUntilSale = date('z',$this->saledate);
	$currentDay=date('z');
	$daysRemain = $daysUntilSale - $currentDay;
return $daysRemain; 
}

function saleOver(){
	if($this->daysLeft() <=0 ){
		return 'this sale is over';
	}else{
	 	return 'You have '.$this->daysLeft().' day(s) before this sale is over';
	}
}

}

$sale = new sales(21,10,2007);

echo $sale->saleOver();
?>

to add differen dates just add the 2 last lines of code

 

$sale2 = new sales(21,12,2007);

 

echo $sale2->saleOver();

 

$sale3 = new sales(10,11,2007);

 

echo $sale3->saleOver();

 

and so on

 

if you just want to know the days with out any extra code look at date('z',$source)

this will return how many days in the year up to the source date;

[clearstatcache]

$freestuffdate = strtotime("07-10-23");    // date format "Y-m-d" for Nov 11, 2007

$today = strtotime(date("Y-m-d"));

if ($freestuffdate >= $today){

    echo "Sale is on!\n";

    $days_to_go = ($freestuffdate - $today) / 86400;  //  there are 86400 minutes in 1 day

    if ($days_to_go < 1) {

        echo "Today is sale day!\n";

    }

    else {

        echo "$days_to_go days to go before sale day!\n";

    }

}

elseif ($freestuffdate<$today){

    echo "Sale is over...\n";

}

 

[clearstatcache]

86400 seconds i mean in 1 day...