joepro0000 Posted April 15, 2006 Share Posted April 15, 2006 I want to pull info out mysql and put it on a php page, but I keep getting errors. heres the script I got.<?php// this line connects to databaseinclude_once("connections/connections.php");$result = mysql_query("SELECT sample, Category FROM category");// we use the names of columns as <row> properties.echo "colors=";while ($row=mysql_fetch_array($result)$line = $row[C].'.';echo $line;?> Quote Link to comment Share on other sites More sharing options...
fenway Posted April 16, 2006 Share Posted April 16, 2006 What errors? MySQL errors? Quote Link to comment Share on other sites More sharing options...
birdie Posted April 16, 2006 Share Posted April 16, 2006 [!--quoteo(post=365374:date=Apr 16 2006, 08:24 PM:name=fenway)--][div class=\'quotetop\']QUOTE(fenway @ Apr 16 2006, 08:24 PM) [snapback]365374[/snapback][/div][div class=\'quotemain\'][!--quotec--]What errors? MySQL errors?[/quote]is it your php syntax by any chance?..try [code]while($row = mysql_fetch_array($result)){$line = $row[c];echo $line;}[/code] Quote Link to comment Share on other sites More sharing options...
joepro0000 Posted April 17, 2006 Author Share Posted April 17, 2006 [!--quoteo(post=365374:date=Apr 16 2006, 03:24 PM:name=fenway)--][div class=\'quotetop\']QUOTE(fenway @ Apr 16 2006, 03:24 PM) [snapback]365374[/snapback][/div][div class=\'quotemain\'][!--quotec--]What errors? MySQL errors?[/quote]>> Parse error: parse error, unexpected T_VARIABLE in /home/content/j/o/e/joepro0000/html/display.php on line 3<<My code is- <? php // Vars - fill these in$address = "localhost"; // The address of your database server. Leave as "localhost" if it's on the same machine, otherwise put the IP or domain name of the machine it's on.$username = "Username"; // MySQL username$password = "Password"; // MySQL password$db = "joepro0000"; // The database to use$table = "Category"; // The table your data is in// Connect to the server$conn = mysql_connect($address, $username, $password);// Select database$rs = mysql_select_db($db, $conn);while($row = mysql_fetch_array($result)){$line = $row[c];echo $line;}?> Quote Link to comment Share on other sites More sharing options...
fenway Posted April 17, 2006 Share Posted April 17, 2006 First, that's definitely a PHP error -- are you sure you can use barewords for hash keys? And which line is 3? Quote Link to comment Share on other sites More sharing options...
joepro0000 Posted April 17, 2006 Author Share Posted April 17, 2006 First, that's definitely a PHP error -- are you sure you can use barewords for hash keys? And which line is 3?<<not sure about barewords, I'm a php newbie. I just want content drawn out my mysql table/database and be placed on a php page. I want to make dynamic text. Quote Link to comment Share on other sites More sharing options...
fenway Posted April 18, 2006 Share Posted April 18, 2006 I understand -- is the "c" a column name? Where does it come from? Quote Link to comment Share on other sites More sharing options...
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