grumpy Posted October 29, 2007 Share Posted October 29, 2007 I have a file-uploading form to uploads a .jpg file and stores its name in a table in my db as co_bannerfile. I'm trying to now write an update form so the user can update their .jpg file. I've successfully written a query to retrieve the stored file's name. How can I display the stored file's name so the user can see its name within the input TYPE="file" field and then decide to update it or not? The following doesn't display the stored file name. What do I have wrong? Thanks for your help. print "\n<br><INPUT NAME=\"the_file\" TYPE=\"file\" SIZE=\"35\" VALUE=\"" . $co_bannerfile . "\">"; Quote Link to comment Share on other sites More sharing options...
trq Posted October 29, 2007 Share Posted October 29, 2007 You cannot use the value attribute with the type file. You will simply need to display the data some other way. Quote Link to comment Share on other sites More sharing options...
grumpy Posted October 29, 2007 Author Share Posted October 29, 2007 Thanks. I was afraid of that! Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.